utin wrote:

Bunuel wrote:

utin wrote:

didn't get this one!!!

Can you please be more specific?

Actually I get confused while solving probability questions.

In this one I am thinking that 3 cars are there and the person has to ride thrice ensuring that he sits in a different car every time.So i took it this way:

probability of getting into 1st car=1/3

probability of getting into 2nd car=1/3

probability of getting into 3rd car=1/3

so final answer=1/27

I know i am not able to understand this one...Please help me clear my concept...

The question asks you:

What is the probability that the passenger will ride in each of the 3 cars?The order the passenger rides in the cars

does not matter, he just has to ride in all three over three consecutive trips. You're trying to compute the probability as if it matters which order he chooses to ride the cars.

First ride: He has a 100% chance of riding in a car he has not yet ridden in.

Second ride: He has ridden in one of the three cars, so he has a 2/3 chance of riding in a car he has not yet ridden in.

Third ride: There's only one car he has not ridden in, so he has a 1/3 chance of choosing the remaining car.