ralucaroman wrote:

HI,

Can smb please help me to understand the below problem?

A certain stock exchange designates each stock with a 1, 2 or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order, constitute a different code, how many diff stocks is it possible to designate with these codes?

A: 2,951

B: 8,125

C:15,600

D: 16,302

E: 18,278

They say that QA is E, however I am not sure how to get there.

I have C 26 taken by 3 = 2,600

C of 26 taken by 2 = 325

C of 26 taken by 1 = 26.

If I add these, I get answer A. Not sure what I am doing wrong.

Thank you,

Andreea

1 letter code - 26 (or you can write 26C1)

2 letter code - 26*26=26^2 (or you can write 26C1*26C1=26^2)

3 letter code - 26*26*26=26^3 (or you can write 26C1*26C1*26C1=26^3)

(For 2 letter, for example, you have 26 choices per each letter, it's 26^2 and not 26C2 or 26P2.)

Total =26+26^2+26^3 =18,278