Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized for You
we will pick new questions that match your level based on your Timer History
Track Your Progress
every week, we’ll send you an estimated GMAT score based on your performance
Practice Pays
we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
It appears that you are browsing the GMAT Club forum unregistered!
Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club
Registration gives you:
Tests
Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.
Applicant Stats
View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more
Books/Downloads
Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!
Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
A certain stock exchange designates each stock with a 1, 2 [#permalink]
10 Nov 2009, 14:50
9
This post was BOOKMARKED
00:00
A
B
C
D
E
Difficulty:
55% (hard)
Question Stats:
67% (02:14) correct
33% (01:41) wrong based on 356 sessions
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
Re: Permutation Problem [#permalink]
10 Nov 2009, 14:57
1
This post received KUDOS
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
Answer e.
if each letter is the same: 26 different combinations 2 letters the same 26^2 all different 26^3
A certain stock exchange designates each stock with a 1, 2 [#permalink]
10 Nov 2009, 14:59
7
This post received KUDOS
Expert's post
4
This post was BOOKMARKED
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
1 letter codes = 26 2 letter codes = 26^2 3 letter codes = 26^3
Total = 26 + 26^2 + 26^3
The problem we are faced now is how to get the answer quickly. Note that the units digit of 26+26^2+26^3 would be (6+6+6=18) 8. Only one answer choice has 8 as unit digit: E (18,278). So I believe, even not calculating 26+26^2+26^3, that answer is E. _________________
Re: Permutation Problem [#permalink]
31 Jan 2011, 08:48
Bunuel wrote:
chicagocubsrule wrote:
The problem we are faced now is how to get the answer quickly. Note that the units digit of 26+26^2+26^3 would be (6+6+6=18) 8. Only one answer choice has 8 as unit digit: E (18,278). So I believe, even not calculating 26+26^2+26^3, that answer is E.
The OA is E. Thanks for poininting out how to spot the correct answer - it took me miserable 4 minutes to multiply 26*26*26 and still I made a wrong calculation
Re: Permutation Problem [#permalink]
14 Feb 2013, 08:18
1
This post received KUDOS
Bunuel wrote:
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
1 letter code=26 2 letter code=26^2 3 letter code=26^3
Total=26+26^2+26^3
The problem we are faced now is how to get the answer quickly. Note that the units digit of 26+26^2+26^3 would be (6+6+6=18) 8. Only one answer choice has 8 as unit digit: E (18,278). So I believe, even not calculating 26+26^2+26^3, that answer is E.
Hi Bunuel,
Firstly let me say that i fully understand your explanation and it makes perfect sense. I am however, finding it difficult to understand why we can't plug in the numbers into the permutations formula i.e. 26+Pm26,2 + Pm26,3 =16,276 which is well short of the 18,278 answer. I'm just wondering when to apply the approach you mentioned above and when to apply the Permutations formula.
Re: Permutation Problem [#permalink]
15 Feb 2013, 02:51
2
This post received KUDOS
Expert's post
1
This post was BOOKMARKED
iwillbeatthegmat wrote:
Bunuel wrote:
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
1 letter code=26 2 letter code=26^2 3 letter code=26^3
Total=26+26^2+26^3
The problem we are faced now is how to get the answer quickly. Note that the units digit of 26+26^2+26^3 would be (6+6+6=18) 8. Only one answer choice has 8 as unit digit: E (18,278). So I believe, even not calculating 26+26^2+26^3, that answer is E.
Hi Bunuel,
Firstly let me say that i fully understand your explanation and it makes perfect sense. I am however, finding it difficult to understand why we can't plug in the numbers into the permutations formula i.e. 26+Pm26,2 + Pm26,3 =16,276 which is well short of the 18,278 answer. I'm just wondering when to apply the approach you mentioned above and when to apply the Permutations formula.
Thanks!
Good question. +1.
Notice that we are told that the letters may be repeated, so AA, BBB, ACC, CAA, .... codes are possible.
Now, 26P2 is the number of ways we can choose 2 distinct letters out of 26 when the order matters, thus it doesn't account for the cases like AA, AAA, ABB, ...
Re: Permutation Problem [#permalink]
18 Sep 2013, 02:56
lagomez wrote:
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
Answer e.
if each letter is the same: 26 different combinations 2 letters the same 26^2 all different 26^3
26^3 + 26^2 + 26 = 18278
what does this statement exactly mean- "if the same letters used in a different order constitute a different code" _________________
Re: Permutation Problem [#permalink]
18 Sep 2013, 03:08
1
This post received KUDOS
Expert's post
2
This post was BOOKMARKED
honchos wrote:
lagomez wrote:
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
Answer e.
if each letter is the same: 26 different combinations 2 letters the same 26^2 all different 26^3
26^3 + 26^2 + 26 = 18278
what does this statement exactly mean- "if the same letters used in a different order constitute a different code"
It means that the order of the letters matters. For example, code AB is different from BA.
Re: Permutation Problem [#permalink]
18 Jan 2014, 05:48
iwillbeatthegmat wrote:
Bunuel wrote:
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
1 letter code=26 2 letter code=26^2 3 letter code=26^3
Total=26+26^2+26^3
The problem we are faced now is how to get the answer quickly. Note that the units digit of 26+26^2+26^3 would be (6+6+6=18) 8. Only one answer choice has 8 as unit digit: E (18,278). So I believe, even not calculating 26+26^2+26^3, that answer is E.
Hi Bunuel,
Firstly let me say that i fully understand your explanation and it makes perfect sense. I am however, finding it difficult to understand why we can't plug in the numbers into the permutations formula i.e. 26+Pm26,2 + Pm26,3 =16,276 which is well short of the 18,278 answer. I'm just wondering when to apply the approach you mentioned above and when to apply the Permutations formula.
Thanks!
1 letter code: 26 2-letter code: P(26,2) + 26 {P(26,2): 2 different numbers and different orders; 26: 2 same numbers} 3-letter code: P(26,3) + P(26, 2)C(3, 1) + 26 {P(26,3): 3 different numbers and different orders; P(26, 2)C(3, 1): 2 different numbers, one of which repeats; 26: 3 same numbers}
Re: A certain stock exchange designates each stock with a 1, 2 [#permalink]
29 Oct 2014, 00:59
I dont know why , but I was thinking for one letter, it's 26, Then for 2 same ones it would be 26^2 2 different ones would mean 26*25 * 2 (because a different order) 3 same would be 26^3, and 3 different would be 26*25*24*3!....Where am I (obviously) double counting?
Re: A certain stock exchange designates each stock with a 1, 2 [#permalink]
29 Oct 2014, 02:48
Expert's post
usre123 wrote:
I dont know why , but I was thinking for one letter, it's 26, Then for 2 same ones it would be 26^2 2 different ones would mean 26*25 * 2 (because a different order) 3 same would be 26^3, and 3 different would be 26*25*24*3!....Where am I (obviously) double counting?
How is 26^2 the number of two same letter words? How is 26^3 the number of three same letter words? Isn't both 26? AA, BB, CC, ..., ZZ and AAA, BBB, CCC, DDD, ..., ZZZ?
26^2 gives the number of ALL 2-letter words possible, the same way as 26^3 gives the number of ALL 3-letter words possible. _________________
Re: A certain stock exchange designates each stock with a 1, 2 [#permalink]
25 Nov 2014, 04:22
Bunuel wrote:
usre123 wrote:
I dont know why , but I was thinking for one letter, it's 26, Then for 2 same ones it would be 26^2 2 different ones would mean 26*25 * 2 (because a different order) 3 same would be 26^3, and 3 different would be 26*25*24*3!....Where am I (obviously) double counting?
How is 26^2 the number of two same letter words? How is 26^3 the number of three same letter words? Isn't both 26? AA, BB, CC, ..., ZZ and AAA, BBB, CCC, DDD, ..., ZZZ?
26^2 gives the number of ALL 2-letter words possible, the same way as 26^3 gives the number of ALL 3-letter words possible.
Re: A certain stock exchange designates each stock with a 1, 2 [#permalink]
12 May 2015, 06:26
Bunuel wrote:
chicagocubsrule wrote:
A certain stock exchange designates each stock with a 1, 2, or 3 letter code, where each letter is selected from the 26 letters of the alphabet. If the letters may be repeated and if the same letters used in a different order constitute a different code, how many different stocks is it possible to uniquely designate with these codes?
a) 2,951 b) 8,125 c) 15,600 d) 16,302 e) 18,278
1 letter codes = 26 2 letter codes = 26^2 3 letter codes = 26^3
Total = 26 + 26^2 + 26^3
The problem we are faced now is how to get the answer quickly. Note that the units digit of 26+26^2+26^3 would be (6+6+6=18) 8. Only one answer choice has 8 as unit digit: E (18,278). So I believe, even not calculating 26+26^2+26^3, that answer is E.
can not say a word for this excellent
gmatclubot
Re: A certain stock exchange designates each stock with a 1, 2
[#permalink]
12 May 2015, 06:26
As I’m halfway through my second year now, graduation is now rapidly approaching. I’ve neglected this blog in the last year, mainly because I felt I didn’...
Perhaps known best for its men’s basketball team – winners of five national championships, including last year’s – Duke University is also home to an elite full-time MBA...
Hilary Term has only started and we can feel the heat already. The two weeks have been packed with activities and submissions, giving a peek into what will follow...