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# A chess player participates in two games. He has 30 percent

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Senior Manager
Joined: 05 May 2003
Posts: 426
Location: Aus
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A chess player participates in two games. He has 30 percent [#permalink]  17 Dec 2003, 21:35
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 2 sessions
A chess player participates in two games. He has 30 percent chance of winning the first game and 20 percent chance of winning the second game. what is the probability that he wins exactly one ?

(A)50%
(B)38%
(C)28%
(D)14%
(E)16%

Intern
Joined: 27 Nov 2003
Posts: 34
Location: Moscow
Followers: 0

Kudos [?]: 1 [0], given: 0

It is B:

1) Probability of winning exactly one game is:

sum of two probabilities:
(winning the first and not winning the second) + (NOT winning the first and winning The second) = 0.3 (1-0.2) + (1-0.3) 0.2 = 0.38 or 38%

2) In order to check, we can solve the other way:

100%- (probability of winning both games + probability of not winning both games) = 1- ( 0.3*0.2+ (1-0.3)(1-0.2)) = 0.38
_________________

me

Director
Joined: 28 Oct 2003
Posts: 503
Location: 55405
Followers: 1

Kudos [?]: 11 [0], given: 0

I used the same method as anvar did in his check example:

Odds of going 1W-1L are 1-(two wins)-(two losses)

1-(.2*.3)-(.8*.7)
Senior Manager
Joined: 05 May 2003
Posts: 426
Location: Aus
Followers: 2

Kudos [?]: 5 [0], given: 0

Thank you. Where can I find more information on these kind of problems ?
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