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A church collected exactly $303 from its members during a [#permalink] ### Show Tags 28 Oct 2006, 23:18 This topic is locked. If you want to discuss this question please re-post it in the respective forum. A church collected exactly$303 from its members during a service. If each member contributed at least $2, what is the greatest number of members that could have attended this particular service? a) 149 b) 150 c) 151 d) 152 e) 153 Senior Manager Joined: 23 May 2005 Posts: 266 Location: Sing/ HK Followers: 1 Kudos [?]: 43 [0], given: 0 ### Show Tags 28 Oct 2006, 23:25 I would go for D. 152 303/2 = 151.5 You round up so you get at least 152 people. _________________ Impossible is nothing Manager Joined: 07 Jun 2006 Posts: 111 Followers: 2 Kudos [?]: 26 [0], given: 0 ### Show Tags 29 Oct 2006, 02:46 Code: You round up so you get at least 152 people According to this, the collection shud add up to 304$ (as each one is contributing atleast 2$) So the Ans is 151.... 150 of the members contributed 2$ while one of them gave 3$Intern Joined: 02 Oct 2006 Posts: 30 Location: Singapore Followers: 0 Kudos [?]: 0 [0], given: 0 ### Show Tags 29 Oct 2006, 08:18 Restriction: Each person AT LEAST$2.

So Since $303 collected, if 151 people came, each gave the min of$2, the amount comes up to 151x2 = $302. That means 150 people gave$2, with one person who gave $3. Important to note that the requirement is that anybody can give more than$2, and not less than $2. So if it was 152, then the amount collected at the very least would be =152x2 =$304. Which already is more than $303. It is not possible that 151 gave$2, and the 152nd person gave $1. Each person needs to give AT LEAST$2.

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29 Oct 2006, 20:10
ggarr wrote:
A church collected exactly $303 from its members during a service. If each member contributed at least$2, what is the greatest number of members that could have attended this particular service?

a) 149
b) 150
c) 151
d) 152
e) 153

watch out with the AT LEAST