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A circle inscribed in an equilateral triangle with side

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A circle inscribed in an equilateral triangle with side [#permalink]  20 Aug 2006, 01:07
A circle inscribed in an equilateral triangle with side length 10. What is the area of inscribed circle?
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25PI/3

When the perpendiculars are dropped from the vertices of the triangles then they meet at the centroid of the circle and the centroid will co-incide with the center of the circle. The ratio of length of line from vertex to centroid to line from centroid to side is 2:1.

So length of perpendicular = √(100-25) = 5*√3
Radius of circle = (5*√3)/3 = 5/√3
Area = 25PI/3
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Hi PS_dahiya

Your answer to this one coincides with the question bank's. What do you mean when you say centroid?
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apollo168 wrote:
Hi PS_dahiya

Your answer to this one coincides with the question bank's. What do you mean when you say centroid?

In the figure attached. meeting point of the three perpendiculars is the centroid.
Attachments

Triangle.JPG [ 5.16 KiB | Viewed 549 times ]

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Oh I get it. So the lower two triangles created are two 30-60-90 triangles so from there you can solve for the radius. Thanks for the diagram
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