Bunuel wrote:
helloanupam wrote:
Bunuel,
Sorry, I could not understand the language of the question and hence probably the answer is not clear to me. If possible , could you reframe the question or explain as to what the question is asking?
Look at the diagram:
Attachment:
untitled.PNG
The car ends
within a half mile of the sign indicating 2.5 miles means that the car should end in
one mile interval, between the signs indicating 2 (2.5-0.5=2) and 3 miles (2+0.5=3), so within the red segment on the diagram.
Now if the car appears somewhere between the blue dots, between 1.5 and 2 miles signs then after traveling 0.5 miles the car will be in the red segment. So in order after traveling 0.5 miles the car to end within the red segment it should appear between 1.5 and 2.5 miles, so within 1 mile interval, as the circumference of the track is 3 miles then the probability of that will be P=favorable/total=1/3. As I mentioned in my previous post actually it doesn't matter where the car appears or what distance it travel, as long as favorable interval in the end is 1 mile and total interval is 3 miles then the probability will be 1/3 miles.
Hope it's clear.
BunuelA small doubt here to be precise the correct ranges would be 2.1,2.2,2.3,2.4,2.5,2.6,2.7,2.8,2.9 as 2.5 miles -/+ 0.4 miles (within 0.5 miles i.e, <=0.5-> <0.4) is between 2.1 and 2.9
probability would be 9/31. (31- 0,0.1,....3.0)
I know the above is wrong but I am having confusion with distance vs exact point transition.(In other words I am calculating exact point like 2.1,2.2,... as in question given 2.5 (within half mile) but unable to know how 2-3-> as OS is capturing the exact condition of question)
Pls help me to figure out where I faltered.