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A circular tub has a band painted around its circumference

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A circular tub has a band painted around its circumference [#permalink]

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26 Aug 2012, 03:19
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A circular tub has a band painted around its circumference, as shown above. What is the surface area of this painted band?

(1) x = 0.5
(2) The height of the tub is 1 meter.

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Re: A circular tub has a band painted around its circumference [#permalink]

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31 Aug 2012, 03:10
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SOLUTION:

A circular tub has a band painted around its circumference, as shown above. What is the surface area of this painted band?

The surface area of the band is circumference of the band (circumference of the tub) multiplied by the width of the band.

(1) x = 0.5. We know the width of the band but not the circumference. Not sufficient.

(2) The height of the tub is 1 meter. From the height of the tub we cannot get neither the width of the band nor the circumference of the tub. Not sufficient.

(1)+(2) We still cannot get the circumference of the tub. Not sufficient.

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Re: A circular tub has a band painted around its circumference [#permalink]

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31 Aug 2012, 03:18
I don't think, this is 650 level. Seems pretty easy to me.

We even don't have to calculate anything here.
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Re: A circular tub has a band painted around its circumference [#permalink]

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31 Aug 2012, 03:25
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Zinsch123 wrote:
I don't think, this is 650 level. Seems pretty easy to me.

We even don't have to calculate anything here.

Changed the difficulty level to 600. Thank you.
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Re: A circular tub has a band painted around its circumference [#permalink]

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31 Aug 2012, 03:44
The answer is E since we don't know the radius of the tub.
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Re: A circular tub has a band painted around its circumference [#permalink]

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30 Jun 2014, 10:18
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Re: A circular tub has a band painted around its circumference [#permalink]

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03 Jun 2015, 00:35
How do I recognize the surface area

As Bunuel told it is (Circumference) (x), where x is the width.

Why can't I say that it is equal to ( (pi) * r^2) (x) ?

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Re: A circular tub has a band painted around its circumference [#permalink]

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03 Jun 2015, 02:45
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anewbeginning wrote:
How do I recognize the surface area

As Bunuel told it is (Circumference) (x), where x is the width.

Why can't I say that it is equal to ( (pi) * r^2) (x) ?

If you consider the band in 2 dimensions, you get a rectangle of length equal to the circumference and with of x. So, the area is $$(2\pi{r})x$$.

$$\pi{r^2})$$ is the area of the top and the base of the cylinder and it has nothing to do with the area of the band.
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Re: A circular tub has a band painted around its circumference   [#permalink] 03 Jun 2015, 02:45
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