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A circular tub has a band painted around its circumference

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A circular tub has a band painted around its circumference [#permalink] New post 26 Aug 2012, 02:19
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TUB.png
TUB.png [ 14.01 KiB | Viewed 4856 times ]
A circular tub has a band painted around its circumference, as shown above. What is the surface area of this painted band?

(1) x = 0.5
(2) The height of the tub is 1 meter.

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Re: A circular tub has a band painted around its circumference [#permalink] New post 31 Aug 2012, 02:10
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A circular tub has a band painted around its circumference, as shown above. What is the surface area of this painted band?

The surface area of the band is circumference of the band (circumference of the tub) multiplied by the width of the band.

(1) x = 0.5. We know the width of the band but not the circumference. Not sufficient.

(2) The height of the tub is 1 meter. From the height of the tub we cannot get neither the width of the band nor the circumference of the tub. Not sufficient.

(1)+(2) We still cannot get the circumference of the tub. Not sufficient.

Answer: E.
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Re: A circular tub has a band painted around its circumference [#permalink] New post 31 Aug 2012, 02:18
I don't think, this is 650 level. Seems pretty easy to me.

We even don't have to calculate anything here.
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Re: A circular tub has a band painted around its circumference [#permalink] New post 31 Aug 2012, 02:25
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Re: A circular tub has a band painted around its circumference [#permalink] New post 31 Aug 2012, 02:44
The answer is E since we don't know the radius of the tub.
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Re: A circular tub has a band painted around its circumference [#permalink] New post 30 Jun 2014, 09:18
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Re: A circular tub has a band painted around its circumference [#permalink] New post 02 Jun 2015, 23:35
How do I recognize the surface area

As Bunuel told it is (Circumference) (x), where x is the width.

Why can't I say that it is equal to ( (pi) * r^2) (x) ?

Please help
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Re: A circular tub has a band painted around its circumference [#permalink] New post 03 Jun 2015, 01:45
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anewbeginning wrote:
How do I recognize the surface area

As Bunuel told it is (Circumference) (x), where x is the width.

Why can't I say that it is equal to ( (pi) * r^2) (x) ?

Please help


If you consider the band in 2 dimensions, you get a rectangle of length equal to the circumference and with of x. So, the area is \((2\pi{r})x\).

\(\pi{r^2})\) is the area of the top and the base of the cylinder and it has nothing to do with the area of the band.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 12 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis ; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) ; 12. Tricky questions from previous years.

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
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Re: A circular tub has a band painted around its circumference   [#permalink] 03 Jun 2015, 01:45
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