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a class has 1/3 in football and 1/4 of students in basket

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Director
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New post 23 Jan 2005, 12:33
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a class has 1/3 in football and 1/4 of students in basket ball. And 12 play both. What is the least possible number fo students in th class

20

22

36

48

144

please answer with explanations
VP
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Joined: 18 Nov 2004
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Kudos [?]: 35 [0], given: 0

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New post 23 Jan 2005, 13:05
48.

All basketball players also play football....12 players.....and 4 football players only play football and we already have a common pool of 12 players.

Backsolving helps.....selection 1 and 2 r out as they r not divisible by 3 and 4...36 doesn't yield the result....as 1/4*36 = 9 basketball players...however, we already know that there r atleast 12 basketball players (the common one)....48 is the least that satisfies everything.

Basketball = 12
Football = 16

Total basket +baseball = 16
Students who do not play anything is = 48-16 = 32
Director
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 [#permalink]

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New post 23 Jan 2005, 17:08
thanks now iget it i was wondering why it was not 36
VP
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New post 23 Jan 2005, 19:31
rxs0005 wrote:
thanks now iget it i was wondering why it was not 36


Yes, it is 48 and not 36. if 36 were the total number of students, then the number of students who play would be negative which is not possible. if 48 were the total number of students, the number of students who play basketball would be 12 and all basketbal players play footvball too.
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New post 24 Jan 2005, 00:39
Both 1/3N and 1/4N must be greater than 12. So N=48.
  [#permalink] 24 Jan 2005, 00:39
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a class has 1/3 in football and 1/4 of students in basket

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