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a class has 1/3 in football and 1/5 of students in basket

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a class has 1/3 in football and 1/5 of students in basket [#permalink] New post 22 Oct 2005, 08:52
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a class has 1/3 in football and 1/5 of students in basket ball. And 12 play both. What is the least possible number fo students in th class

20

22

60

48

150
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 [#permalink] New post 22 Oct 2005, 10:16
48??

Not sure about straight math.. my approach was more of a "best fit"

(1/3)rd + (1/5)th - 12 = X Students
So we are looking for a multiple of 3*5=15..... so X+12 needs to be a multiple of 15.

Only 48+12=60 gives us a multiple of 15. So 48.
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 [#permalink] New post 22 Oct 2005, 10:49
Tried the regular formula, but i got total students as 25.xx.

g1 + g2 - both + neither = all (assume neither = 0)

1/3*x + 1/5 * x - 12 = x

Solving above I got 25.xx.

However, I go with 60 as this is the least number that is divisible by 3 * 5 and greater than 25.

What is OA?
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 [#permalink] New post 24 Oct 2005, 09:05
For minimum no. of students, the condition should be that all the students who play basketball (since they are less than the no. of students who play football) also play football.
So, students who play both football and basketball = 1/5
But 1/5 * x = 12 => x= 60
  [#permalink] 24 Oct 2005, 09:05
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a class has 1/3 in football and 1/5 of students in basket

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