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A clothing store acquired an item at a cost of x dollars and [#permalink]
 06 Aug 2008, 12:12
Question Stats:
65% (01:46) correct
34% (01:20) wrong based on 2 sessions
A clothing store acquired an item at a cost of x dollars and sold the item for y dollars. The store’s gross profit from the item was what percent of its cost for the item? (1) y – x = 20 (2) y / x = 5 / 4
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Re: Clothing Store - DS Question [#permalink]
06 Aug 2008, 12:21
chan4312 wrote: A clothing store acquired an item at a cost of x dollars and sold the item for y dollars. The store’s gross profit from the item was what percent of its cost for the item?
(1) y – x = 20
2) y / x = 5 / 4
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient. Answer is C. Stat-1 tells about the profit but does not tell about the original cost. Using 1 and 2 both you get both the value of x and the $20 profit on it. Hope I am right.
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Re: Clothing Store - DS Question [#permalink]
06 Aug 2008, 12:28
chan4312 wrote: A clothing store acquired an item at a cost of x dollars and sold the item for y dollars. The store’s gross profit from the item was what percent of its cost for the item?
(1) y – x = 20
2) y / x = 5 / 4
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient. gross profit = n (y-x) % = n(y-x)/nx = (y-x) / x (1) y – x = 20 (y-x) / x = 20/x*100 not suffcieint.. we don't the x 2) suffciient. (y-x) / x = y/x-1 % = 5/4-1*100 B
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Re: Clothing Store - DS Question [#permalink]
06 Aug 2008, 12:38
x2suresh wrote: gross profit = n (y-x)
% = n(y-x)/nx = (y-x) / x
(1) y – x = 20
(y-x) / x = 20/x*100
not suffcieint.. we don't the x
2) suffciient.
(y-x) / x = y/x-1 % = 5/4-1*100
B  sorry....PR told me not to use too much algebra...I guess they were wrong 
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Re: Clothing Store - DS Question [#permalink]
06 Aug 2008, 17:20
chan4312 wrote: A clothing store acquired an item at a cost of x dollars and sold the item for y dollars. The store’s gross profit from the item was what percent of its cost for the item?
(1) y – x = 20
2) y / x = 5 / 4
A. Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
B. Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
C. BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
D. EACH statement ALONE is sufficient.
E. Statements (1) and (2) TOGETHER are NOT sufficient. Clearly B Here the cost price =x selling price=y gross profit =y-x gross profit % = (y-x) /x = (y/x)-1 ------->eqn I Now (1) is INSUFFI since we y-x=20 but no clue about x (2) is SUFFI we know y/x=5/4 IMO B
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Re: Clothing Store - DS Question [#permalink]
06 Aug 2008, 19:50
B for me as well. We need to find (y-x)/x, or, in other terms, y/x - 1. This relationship is provided in stat 2, but not 1.
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Re: A clothing store required...... [#permalink]
26 Oct 2010, 23:38
monirjewel wrote: A clothing store acquired an item at a cost of x dollars and sold the item for y dollars. The store's gross profit from the item was what percent of its cost for the item?
(1) y-x=20
(2) y/x=5/4 Question requires {(y-x)/x}*100 or {(y/x)-1}*100 we can get this from (2), Hence answer is B.
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Re: A clothing store required...... [#permalink]
28 Oct 2010, 01:46
The question requires ((y-x)/x)*100
1. From this statement we know that (y-x) = 20 >> (20/x)*100 >> Insufficient
2. From this statement we know that y/x = 5/4 or 5x = 4y >> y = 5/4x >>> Insufficient
Whereas 1 and 2 combined gives us ((y-x)/x)*100 >> ((5/4x - x)/x)*100 = (20/x)*100 >> (5/4x - x)/x = 20/x
>> (1/4x) /x = 20/x >> 1/4 = 20/x >> x = 80
knowing y-x and x we can write ((y-x)/x)*100 as (20/80)*100 >> 25%
Therefore i will go for C !
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Re: A clothing store required...... [#permalink]
20 Oct 2011, 12:58
ankitranjan wrote: monirjewel wrote: A clothing store acquired an item at a cost of x dollars and sold the item for y dollars. The store's gross profit from the item was what percent of its cost for the item?
(1) y-x=20
(2) y/x=5/4 Question requires {(y-x)/x}*100 or {(y/x)-1}*100 we can get this from (2), Hence answer is B. This is my working too. From Rephrasing the original question, it boils down to (Y/X - 1)*100. So all we really need is Y/X which is provided in B and hence is the answer.
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Re: A clothing store required......
[#permalink]
20 Oct 2011, 12:58
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