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A club collected exactly $599 from its members. If each

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A club collected exactly $599 from its members. If each [#permalink] New post 26 Sep 2012, 11:34
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A club collected exactly $599 from its members. If each member contributed at least $12, what is the greatest number of members the club could have?

(A) 43
(B) 44
(C) 49
(D) 50
(E) 51
[Reveal] Spoiler: OA

Last edited by Bunuel on 26 Sep 2012, 12:08, edited 1 time in total.
Renamed the topic.
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Re: A club collected exactly $599 from its members. If each [#permalink] New post 26 Sep 2012, 12:17
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Archit143 wrote:
A club collected exactly $599 from its members. If each member contributed at least $12, what is the greatest number of members the club could have?

(A) 43
(B) 44
(C) 49
(D) 50
(E) 51


Obviously club could not have 50 or more members, since $12*50=$600>$599. What about 49? If 48 members contributes $12 ($12*48=$576) and 1 member contributed the remaining $23, then the club would have is 48+1=49.

Answer: C.

OR: 12x\leq{$599} --> x\leq{49\frac{11}{12}} --> x=49 (since x must be an integer).

Answer: C.
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Re: A club collected exactly $599 from its members. If each   [#permalink] 26 Sep 2012, 12:17
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