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A club collected exactly $599 from its members. If each

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A club collected exactly $599 from its members. If each [#permalink]

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A club collected exactly $599 from its members. If each member contributed at least $12, what is the greatest number of members the club could have?

(A) 43
(B) 44
(C) 49
(D) 50
(E) 51
[Reveal] Spoiler: OA

Last edited by Bunuel on 26 Sep 2012, 11:08, edited 1 time in total.
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Re: A club collected exactly $599 from its members. If each [#permalink]

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Archit143 wrote:
A club collected exactly $599 from its members. If each member contributed at least $12, what is the greatest number of members the club could have?

(A) 43
(B) 44
(C) 49
(D) 50
(E) 51


Obviously club could not have 50 or more members, since $12*50=$600>$599. What about 49? If 48 members contributes $12 ($12*48=$576) and 1 member contributed the remaining $23, then the club would have is 48+1=49.

Answer: C.

OR: \(12x\leq{$599}\) --> \(x\leq{49\frac{11}{12}}\) --> \(x=49\) (since x must be an integer).

Answer: C.
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Re: A club collected exactly $599 from its members. If each [#permalink]

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New post 02 Jul 2014, 01:47
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Rounded off 599 to 600 (Its divisible of 12)

\(\frac{600}{12} = 50\)

Members should be atleast 1 less that 50

50-1 = 49

Answer = C
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Re: A club collected exactly $599 from its members. If each [#permalink]

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New post 30 Jun 2014, 21:34
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Re: A club collected exactly $599 from its members. If each [#permalink]

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New post 30 May 2015, 04:41
Estimate, you don't need to divide here to get the answer:

12X<=600 --> X<=50, But we rounded up, so the real number must be <50 --> 49 (C)
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Re: A club collected exactly $599 from its members. If each [#permalink]

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New post 21 Jun 2016, 09:34
Archit143 wrote:
A club collected exactly $599 from its members. If each member contributed at least $12, what is the greatest number of members the club could have?

(A) 43
(B) 44
(C) 49
(D) 50
(E) 51


Let's first divide= 599 by 12 (the minimum amount each member could contribute) and then use the remainder to finish the problem.

599/12 = 49 R 11

This means that: 49 people x $12 + 1 person x $11 = $599

We see that if 49 members each contribute $12, someone would have to contribute the extra $11. Note that, since each member contributed at least $12, the $11 could not have come from an additional member. Therefore, the extra $11 must have been contributed by one (or more) of the existing 49 members. Regardless of who contributed the extra $11, the maximum number of members the club could have is 49.

Answer is C.
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Re: A club collected exactly $599 from its members. If each   [#permalink] 21 Jun 2016, 09:34
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