A college has two departments, finance dept. and accounting : DS Archive
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# A college has two departments, finance dept. and accounting

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A college has two departments, finance dept. and accounting [#permalink]

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23 Nov 2005, 18:51
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A college has two departments, finance dept. and accounting dept. The ratio of the teachers in two dept. is 2:1. What is the ratio of the number of teachers doing a part-time job to the number of the teachers not doing?

1) 1/2 of the teachers in accounting dept. do part-time jobs.
2) The ratio of the teachers doing part-time jobs in two departments is 3:4
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23 Nov 2005, 19:23
arsenicdoped wrote:
A college has two departments, finance dept. and accounting dept. The ratio of the teachers in two dept. is 2:1. What is the ratio of the number of teachers doing a part-time job to the number of the teachers not doing?

1) 1/2 of the teachers in accounting dept. do part-time jobs.
2) The ratio of the teachers doing part-time jobs in two departments is 3:4

1) we don't know the number of teachers not/do the part-time jobs --> insuff

2). The ratio of the teachers doing part-time jobs in two departments is 3:4---> we don't know the order of this ratio --> insuff anyway

1and 2: as we don't know the order of the ratio -->insuff

I don't know if the question assume the ratio is of finance to accounting or not
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23 Nov 2005, 19:30
I am myself not very sure of the question. But if we assume the order of the second one given. I think C will be the correct answer.

Any comment on my reasoning.
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23 Nov 2005, 19:38
Note:
1) If order is assumed in Statement (2), this is the working:

Using (1), we do not know how many part time teachers in finance dept. (1) is not sufficient.
Using (2), we have:

# of teachers = x
# of finance teachers = 2x/3
# of accounting teachers = x/3
# of part time finance teachers = 3x/7
$of part time accounting teachers = 4x/7 We can now compute ratio of full time: part time teachers. (2) is sufficient. Ans: B However, if order cannot be assumed, then the answer is D. Manager Joined: 30 Aug 2005 Posts: 186 Followers: 1 Kudos [?]: 15 [0], given: 0 ### Show Tags 27 Nov 2005, 06:13 ans is C. I drew the grid, Plugged in a value for total number of employees. Director Joined: 26 Sep 2005 Posts: 576 Location: Munich,Germany Followers: 1 Kudos [?]: 18 [0], given: 0 ### Show Tags 24 Dec 2005, 01:40 B is suff here. (order assumed) Manager Joined: 30 Jan 2005 Posts: 143 Followers: 1 Kudos [?]: 1 [0], given: 0 ### Show Tags 24 Dec 2005, 05:58 i got with B.....order assumed......wats the OA Manager Joined: 24 Oct 2005 Posts: 52 Followers: 1 Kudos [?]: 5 [0], given: 0 ### Show Tags 24 Dec 2005, 13:35 A college has two departments, finance dept. and accounting dept. The ratio of the teachers in two dept. is 2:1. What is the ratio of the number of teachers doing a part-time job to the number of the teachers not doing? 1) 1/2 of the teachers in accounting dept. do part-time jobs. 2) The ratio of the teachers doing part-time jobs in two departments is 3:4 1) -- We don't know how many part-time teachers are there in Finance dept..--> Insuff 2) Assuming the ratio 3:4 is finance : accounting respectively, then I go with B, 2 alone is Sufficient If this question comes in the real exam the same way as it appears here, I would pick E. may be this is one of the GMAT Traps. Senior Manager Joined: 11 Nov 2005 Posts: 328 Location: London Followers: 1 Kudos [?]: 11 [0], given: 0 ### Show Tags 24 Dec 2005, 14:10 I think it is C. Explanation, lets assume the total number of teachers 24 24:- 16 teachers in Fin and 8 teachers in Acc Stat 1. half teacher in Acc is part time, so 4 PT and 4FT - NOT SUFFICIENT Stat2. PT job in two department is 3:4, means 3 PT teacher in Fin for every 4 PT teacher in Acc, NOT SUFFICIENT However combined together stat 1&2. when there are 8 teachers in Acc, and half is PT, means 4 are PT. This is same as 3 PT in Fin, so 13 FT and 3 PT. THE RATIO OF PT/FT = (3+4)/(13+4) =7/17 both statement together are sufficient! (assuming theorder is same) Any comments? please! Senior Manager Joined: 11 Nov 2005 Posts: 328 Location: London Followers: 1 Kudos [?]: 11 [0], given: 0 ### Show Tags 24 Dec 2005, 14:19 if the number of teachers is 48 ,for example, how will you go around with B only? ywilfred wrote: Note: 1) If order is assumed in Statement (2), this is the working: Using (1), we do not know how many part time teachers in finance dept. (1) is not sufficient. Using (2), we have: # of teachers = x # of finance teachers = 2x/3 # of accounting teachers = x/3 # of part time finance teachers = 3x/7$ of part time accounting teachers = 4x/7

We can now compute ratio of full time: part time teachers.

(2) is sufficient.

Ans: B

However, if order cannot be assumed, then the answer is D.
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24 Dec 2005, 22:38
If order is assumed as (F:A) then its C else E.

Here I go
F is finance, A is accounting. 1 is permanent teachers and 2 is part-time teachers. So given is

F1+F2 : A1+A2 = 2:1

1) A1:A2 = 1:1
So F1+F2 : A + A = 2:1 there is no information about F2 so we can not find F2 + A2 : F1+ A1. INSUFF
2) F2: A2 = 3:4. By this we can not find the sum F2 + A2 or F1 + A1. INSUFF

Both combined

A1:A2 = 2:1 and F2:A2 = 3:4
Now assume total = x
From given F:A = 2x/3 : x/3

From 1 A1 = x/6 and A2 = x/6

From 2 F2 = (x/6)* (3/4) = x/8. So F1 = (2x/3) - x/8 = 13x/24

So (F2+A2)/(F1+A1) = [(x/8) + (x/6)] / [(13x/24) + (x/6)] = 7/17 SUFF
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24 Dec 2005, 22:38
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