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Manager
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A college has two departments, finance dept. and accounting [#permalink]
 23 Nov 2005, 19:51
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A college has two departments, finance dept. and accounting dept. The ratio of the teachers in two dept. is 2:1. What is the ratio of the number of teachers doing a part-time job to the number of the teachers not doing?
1) 1/2 of the teachers in accounting dept. do part-time jobs.
2) The ratio of the teachers doing part-time jobs in two departments is 3:4
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arsenicdoped wrote: A college has two departments, finance dept. and accounting dept. The ratio of the teachers in two dept. is 2:1. What is the ratio of the number of teachers doing a part-time job to the number of the teachers not doing?
1) 1/2 of the teachers in accounting dept. do part-time jobs.
2) The ratio of the teachers doing part-time jobs in two departments is 3:4
1) we don't know the number of teachers not/do the part-time jobs --> insuff
2). The ratio of the teachers doing part-time jobs in two departments is 3:4---> we don't know the order of this ratio --> insuff anyway
1and 2: as we don't know the order of the ratio -->insuff
I don't know if the question assume the ratio is of finance to accounting or not 
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Manager
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I am myself not very sure of the question. But if we assume the order of the second one given. I think C will be the correct answer.
Any comment on my reasoning.
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GMAT Club Legend
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Note:
1) If order is assumed in Statement (2), this is the working:
Using (1), we do not know how many part time teachers in finance dept. (1) is not sufficient.
Using (2), we have:
# of teachers = x
# of finance teachers = 2x/3
# of accounting teachers = x/3
# of part time finance teachers = 3x/7
$ of part time accounting teachers = 4x/7
We can now compute ratio of full time: part time teachers.
(2) is sufficient.
Ans: B
However, if order cannot be assumed, then the answer is D.
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Manager
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ans is C.
I drew the grid, Plugged in a value for total number of employees.
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Director
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B is suff here. (order assumed)
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Manager
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i got with B.....order assumed......wats the OA
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Manager
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A college has two departments, finance dept. and accounting dept. The ratio of the teachers in two dept. is 2:1. What is the ratio of the number of teachers doing a part-time job to the number of the teachers not doing?
1) 1/2 of the teachers in accounting dept. do part-time jobs.
2) The ratio of the teachers doing part-time jobs in two departments is 3:4
1) -- We don't know how many part-time teachers are there in Finance dept..--> Insuff
2) Assuming the ratio 3:4 is finance : accounting respectively, then I go with B, 2 alone is Sufficient
If this question comes in the real exam the same way as it appears here, I would pick E. may be this is one of the GMAT Traps.
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Senior Manager
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I think it is C.
Explanation, lets assume the total number of teachers 24
24:- 16 teachers in Fin and 8 teachers in Acc
Stat 1. half teacher in Acc is part time, so 4 PT and 4FT - NOT SUFFICIENT
Stat2. PT job in two department is 3:4, means 3 PT teacher in Fin for every 4 PT teacher in Acc, NOT SUFFICIENT
However combined together stat 1&2.
when there are 8 teachers in Acc, and half is PT, means 4 are PT. This is same as 3 PT in Fin, so 13 FT and 3 PT.
THE RATIO OF PT/FT = (3+4)/(13+4) =7/17
both statement together are sufficient! (assuming theorder is same)
Any comments? please!
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Senior Manager
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if the number of teachers is 48 ,for example, how will you go around with B only?
ywilfred wrote: Note:
1) If order is assumed in Statement (2), this is the working:
Using (1), we do not know how many part time teachers in finance dept. (1) is not sufficient.
Using (2), we have:
# of teachers = x
# of finance teachers = 2x/3
# of accounting teachers = x/3
# of part time finance teachers = 3x/7
$ of part time accounting teachers = 4x/7
We can now compute ratio of full time: part time teachers.
(2) is sufficient.
Ans: B
However, if order cannot be assumed, then the answer is D.
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CEO
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If order is assumed as (F:A) then its C else E.
Here I go
F is finance, A is accounting. 1 is permanent teachers and 2 is part-time teachers. So given is
F1+F2 : A1+A2 = 2:1
1) A1:A2 = 1:1
So F1+F2 : A + A = 2:1 there is no information about F2 so we can not find F2 + A2 : F1+ A1. INSUFF
2) F2: A2 = 3:4. By this we can not find the sum F2 + A2 or F1 + A1. INSUFF
Both combined
A1:A2 = 2:1 and F2:A2 = 3:4
Now assume total = x
From given F:A = 2x/3 : x/3
From 1 A1 = x/6 and A2 = x/6
From 2 F2 = (x/6)* (3/4) = x/8. So F1 = (2x/3) - x/8 = 13x/24
So (F2+A2)/(F1+A1) = [(x/8) + (x/6)] / [(13x/24) + (x/6)] = 7/17 SUFF
_________________
SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008
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