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A committee is composed of w women and m men. If 3 women and

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A committee is composed of w women and m men. If 3 women and [#permalink] New post 20 Dec 2012, 05:30
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95% (01:42) correct 5% (01:10) wrong based on 222 sessions
A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)
[Reveal] Spoiler: OA
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Re: A committee is composed of w women and m men. If 3 women and [#permalink] New post 20 Dec 2012, 05:32
Expert's post
Walkabout wrote:
A committee is composed of w women and m men. If 3 women and 2 men are added to the committee, and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by

(A) w/m
(B) w/(w+m)
(C) (w+3)/(m+2)
(D) (w+3)/(w+m+3)
(E) (w+3)/(w+m+5)


The total number of members on the enlarged committee is (w+3)+(m+2)=w+m+5;
The total number of women on the enlarged committee is w+3.

Thus, the probability that a woman is selected is P=favorable/total=(w+3)/(w+m+5).

Answer: E.
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Kudos [?]: 51 [0], given: 105

Re: A committee is composed of w women and m men. If 3 women and [#permalink] New post 30 Dec 2013, 00:12
Bunuel,
Why is this incorrect ?

Let no of Women =10
Let no of Men =8
After addition of new ppl Women =13 , Men =10 , total =23

To select 1 woman out of the total (23)

13/23

On substituting in the answers B fits.
What am i doing wrong ?..
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Re: A committee is composed of w women and m men. If 3 women and [#permalink] New post 30 Dec 2013, 00:22
Expert's post
thinktank wrote:
Bunuel,
Why is this incorrect ?

Let no of Women =10
Let no of Men =8
After addition of new ppl Women =13 , Men =10 , total =23

To select 1 woman out of the total (23)

13/23

On substituting in the answers B fits.
What am i doing wrong ?..


If you substitute w=10 and m=8 in option B you get w/(w+m)=8/18 not 13/23, while option E gives (w+3)/(w+m+5)=13/23. Notice that w and m are the numbers of women and men BEFORE 3 women and 2 men were added to the committee.

Hope it's clear.
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PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

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Manager
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Concentration: Operations, Marketing
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Kudos [?]: 51 [0], given: 105

Re: A committee is composed of w women and m men. If 3 women and [#permalink] New post 30 Dec 2013, 00:58
Bunuel,
How can we assume that we have to use the initial number of men and women to calculate the final result. the question states that

'and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by'

So we have to find the possibility of choosing 1 Woman out of the total number of women (13) ie) 13C1..Isnt that what the question means ??
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Joined: 02 Sep 2009
Posts: 23064
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Kudos [?]: 27244 [0], given: 2725

Re: A committee is composed of w women and m men. If 3 women and [#permalink] New post 30 Dec 2013, 01:01
Expert's post
thinktank wrote:
Bunuel,
How can we assume that we have to use the initial number of men and women to calculate the final result. the question states that

'and if one person is selected at random from the enlarged committee, then the probability that a woman is selected can be represented by'

So we have to find the possibility of choosing 1 Woman out of the total number of women (13) ie) 13C1..Isnt that what the question means ??


A committee is composed of W women and M men. Then 3 women and 2 men are added. W and M are initial numbers of women and men,
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: A committee is composed of w women and m men. If 3 women and   [#permalink] 30 Dec 2013, 01:01
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