Find all School-related info fast with the new School-Specific MBA Forum
Learn more about the recent changes... close

It is currently 23 May 2013, 18:37
Customize  |  Hide

Search
Register
New posts
Unanswered

A committee of 3 people is to be chosen from four married

  Question banks Downloads My Bookmarks Reviews  
  Oldest Best Reply
Search for:
 
Print view
First unread post
Author Message
TAGS:
Intern
Intern
Joined: 20 Apr 2006
Posts: 39
Followers: 0

Kudos [?]: 0 [0], given: 0

A committee of 3 people is to be chosen from four married [#permalink] New post 01 Aug 2006, 05:11
A committee of 3 people is to be chosen from four married couple. What is the number of different committees that can be chosen if 2 people who are married to each other cannot both serve on the committee.

1. 16
2. 24
3. 26
4. 30.
5. 32
CEO
CEO
User avatar
Joined: 20 Nov 2005
Posts: 2934
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
Followers: 7

Kudos [?]: 37 [0], given: 0

GMAT Tests User
 [#permalink] New post 01 Aug 2006, 09:25
E
Number of ways of choosing first person = 8
Number of ways of choosing second person = 6 (Out of 7 remaning, anyone can be chosen except his/her partner)
Number of ways of choosing third person = 4 (Out of 6 remaning anyone can be chosen except partners of two selected person)

Total = 8*6*4
But this contain duplicates. To remove duplicates divide by the factorial of number of people in the committee.
So total ways = 8*6*4/3! = 32
_________________

SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Intern
Intern
Joined: 20 Apr 2006
Posts: 39
Followers: 0

Kudos [?]: 0 [0], given: 0

 [#permalink] New post 01 Aug 2006, 09:42
Thanks for the answer. Can this question also be solved using the xCn (combination) formula?
Intern
Intern
Joined: 02 May 2006
Posts: 25
Followers: 0

Kudos [?]: 0 [0], given: 0

Re [#permalink] New post 01 Aug 2006, 10:02
Yes, that is:

8C3-4*6C1

Where, 8C3 is the different ways you can choose 3 persons from the 8 possibilities.
PPX=groups where the partners are together..so that is 4*6=24

56-24=32
SVP
SVP
User avatar
Joined: 30 Mar 2006
Posts: 1744
Followers: 1

Kudos [?]: 12 [0], given: 0

GMAT Tests User
 [#permalink] New post 02 Aug 2006, 03:51
E 32

Number of ways 3 people can be chosen from 8 people = 8C3 = 56

When the fist married couple is chosen .... number of ways to choose the third person = 6
Similarily since there are four couples.... number of ways to choose couple in the commitee = 4*6 = 24

Hence number of ways NOT to choose any couple = 56-24 = 32
  [#permalink] 02 Aug 2006, 03:51
    Similar topics Author Replies Last post
Similar
Topics:
 New posts A commitee of three people is to be chosen from four married TriColor 5 07 Jun 2006, 12:20
New posts A committe of three people is to be chosen from four married mahesh004 1 02 Oct 2006, 19:27
New posts A committee of 3 people is to be chosen from four married chadhazen6 2 03 Oct 2006, 17:49
New posts A committee of 3 people is to be chosen from 4 married tharunv 1 30 Oct 2008, 18:37
Popular new posts 15 EXPERTS_POSTS_IN_THIS_TOPIC A committee of 3 people is to be chosen from four married LM 23 11 May 2010, 12:35
Display posts from previous: Sort by

A committee of 3 people is to be chosen from four married

  Question banks Downloads My Bookmarks Reviews  
Print view
First unread post

Moderators: Bunuel, VeritasPrepKarishma

Search for:


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.

Main navigation

GMAT Resources

Partners

MBA Resources

www.gmac.com|www.mba.com