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A committee of 3 people is to be chosen from four married

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A committee of 3 people is to be chosen from four married [#permalink] New post 03 Oct 2006, 17:49
A committee of 3 people is to be chosen from four married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot be placed on the same committee?
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Re: GMAT Prep Probability [#permalink] New post 03 Oct 2006, 20:30
This question sounds familiar. I think someone else had also posted it recently.
8C3 - 4x6 = 32

3 people can be chosen in 8C3 ways. There are 24 ways in which a married couple will always be there on the commitee
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 [#permalink] New post 03 Oct 2006, 20:42
The possible combinations if we leave the wives aside :-D are 4

So if we replace the husband with his wife, then we have another 4 combinations.

So the possible combinations are:
4*2*4=32
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  [#permalink] 03 Oct 2006, 20:42
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