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# A committee of 3 people is to be chosen from four married

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Joined: 09 Jun 2006
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A committee of 3 people is to be chosen from four married [#permalink]

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03 Oct 2006, 17:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A committee of 3 people is to be chosen from four married couples. What is the number of different committees that can be chosen if two people who are married to each other cannot be placed on the same committee?
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Re: GMAT Prep Probability [#permalink]

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03 Oct 2006, 20:30
This question sounds familiar. I think someone else had also posted it recently.
8C3 - 4x6 = 32

3 people can be chosen in 8C3 ways. There are 24 ways in which a married couple will always be there on the commitee
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03 Oct 2006, 20:42
The possible combinations if we leave the wives aside are 4

So if we replace the husband with his wife, then we have another 4 combinations.

So the possible combinations are:
4*2*4=32
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[#permalink] 03 Oct 2006, 20:42
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# A committee of 3 people is to be chosen from four married

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