Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A Committee of 6 is chosen from 8 men and 5 women, so as to [#permalink]
16 Apr 2006, 18:08

A Committee of 6 is chosen from 8 men and 5 women, so as to contain at least 2 men and 3 women. How many different committees could be formed if two of the men refuse to serve together?

there are 2 possible scenarios 2M,4W and 3M,3W
so,

(2C8 * 4C5) + (3C8 * 3C5) = 140 + 560 = 700 possible combinations
You know that there are invalid cases where the two men are together, so by process of elimination, E (635) is the only valid answer, however I would suspect that the real GMAT would put a few more choices under 700 so you'd have to solve the whole thing.

so 700 total cases, minus the cases where the two jerks are together.
all of comboas that have 2 men that are those two, are invalid, so thats the two of them, paired with every possible set of women, ->5
The 3-men sets that are invalid are the two of them, paired with each of the remaining six men(6), pair each of those with every possible combination of 3 women(10) 6*10 = 60.
so there are 5 invalid combos that have 2 men, and 60 invalid combos that have 3 men.

Can you teach businessmen to be ethical? : he mind is divided into two parts that sometimes conflict, like a small rider sitting on the back of a very...

HBS: Reimagining Capitalism: Business and Big Problems : Growing income inequality, poor or declining educational systems, unequal access to affordable health care and the fear of continuing economic distress...

Over the last week my Facebook wall has been flooded with most positive, almost euphoric emotions: “End of a fantastic school year”, “What a life-changing year it’s been”, “My...