Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 24 Aug 2016, 20:29

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A company bought a load of water-damaged copy paper,

Author Message
Manager
Joined: 25 Jun 2003
Posts: 93
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

11 Aug 2003, 10:14
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ? _________________ Brainless SVP Joined: 03 Feb 2003 Posts: 1603 Followers: 8 Kudos [?]: 210 [0], given: 0 [#permalink] ### Show Tags 11 Aug 2003, 10:18 I remember I saw it in Princeton. A problem with a twist. I hate it. Manager Joined: 10 Jun 2003 Posts: 210 Location: Maryland Followers: 2 Kudos [?]: 7 [0], given: 0 Re: Problem Solving 1 [#permalink] ### Show Tags 11 Aug 2003, 10:29 Brainless wrote: A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be$0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?

.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.
Manager
Joined: 25 Jun 2003
Posts: 93
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

11 Aug 2003, 15:21
mciatto wrote:
Brainless wrote:
A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be $0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ? .64 .72 * 2/3 = 48 to get what each ream would cost if they were all salvageable. 48 * 4/3 = 64 to get the answer. Your answer is right. But still I am unable to see it !! A detailed explanation plz !! _________________ Brainless GMAT Instructor Joined: 07 Jul 2003 Posts: 770 Location: New York NY 10024 Schools: Haas, MFE; Anderson, MBA; USC, MSEE Followers: 18 Kudos [?]: 167 [0], given: 0 Re: Problem Solving 1 [#permalink] ### Show Tags 11 Aug 2003, 15:38 Brainless wrote: mciatto wrote: Brainless wrote: A company bought a load of water-damaged copy paper, estimating that 2/3 of the reams could be slavaged, in which case the cost per salvageable ream would be$0.72. If it later turned out that 3/4 of reams were salvageable, then what was the actual cost per salvageable ream ?

.64

.72 * 2/3 = 48 to get what each ream would cost if they were all salvageable.

48 * 4/3 = 64 to get the answer.

Your answer is right. But still I am unable to see it !!
A detailed explanation plz !!

Let C = cost of the reams
Let R = original number of reams.

C = (2/3)R * .72 [Cost = number of good reams x cost per good ream]
C = (3/4)R * X [Cost = number of good reams x cost per good ream]

The "cost" of the paper is the same in both cases so:

(2/3)R * .72 = (3/4)R * X

Now solve for X.

X = (2/3)(4/3)* .72 = .64.
_________________

Best,

AkamaiBrah
Former Senior Instructor, Manhattan GMAT and VeritasPrep
Vice President, Midtown NYC Investment Bank, Structured Finance IT
MFE, Haas School of Business, UC Berkeley, Class of 2005
MBA, Anderson School of Management, UCLA, Class of 1993

Re: Problem Solving 1   [#permalink] 11 Aug 2003, 15:38
Display posts from previous: Sort by