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A company has assigned a distinct 3-digit code number to

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Manager
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A company has assigned a distinct 3-digit code number to [#permalink] New post 01 Aug 2008, 04:13
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A company has assigned a distinct 3-digit code number to each of its 330 employees.
Each code number was formed from the digits
2, 3, 4, 5, 6, 7, 8, 9
and no digit appears more than once in any one code number. How many unassigned code numbers
are there?
A. 6
B. 58
C. 174
D. 182
E. 399
Senior Manager
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Joined: 16 Jul 2008
Posts: 290
Schools: INSEAD Dec'10
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Re: A distinct 3-digit code number [#permalink] New post 01 Aug 2008, 04:35
IMO A.

8x7x6 = 336. So there are 6 left.
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Manager
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Re: A distinct 3-digit code number [#permalink] New post 01 Aug 2008, 07:16
Thank you,
OA: A
I think I should spend more time on combinations, permutations...I am often confused when I face them.
Would anyone give me some suggestions. Thanks in advance.
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Re: A distinct 3-digit code number [#permalink] New post 02 Aug 2008, 23:14
fiesta wrote:
A company has assigned a distinct 3-digit code number to each of its 330 employees.
Each code number was formed from the digits
2, 3, 4, 5, 6, 7, 8, 9
and no digit appears more than once in any one code number. How many unassigned code numbers
are there?
A. 6
B. 58
C. 174
D. 182
E. 399


8*7*6 are possible combinations out of which 330 are used => unsused is 6 IMO A
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Re: A distinct 3-digit code number [#permalink] New post 22 Jan 2010, 04:23
There are 8 numbers to choose from (2, 3, 4, 5, 6, 7, 8, 9)

The codes contain 3 of these 8 digits, without repetition

So, the total number of possible codes are 8*7*6 = 336

336 - 330 = 6

A) 6
Re: A distinct 3-digit code number   [#permalink] 22 Jan 2010, 04:23
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