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A company hired a printer to produce a total of x + 1 [#permalink]

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21 Feb 2012, 01:45

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A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

66% (03:33) correct
34% (02:48) wrong based on 357 sessions

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A company hired a printer to produce a total of x + 1 envelopes. The job consisted of two types of envelopes, 2¢ envelopes and 5¢ envelopes. If the company requested 3 more 2¢ envelopes than 5¢ envelopes, which of the following expressions denotes the cost, in cents, of the total x + 1 envelopes ?

A) 3x + 1

B) (7x - 2)/2

C) 11x + 31

D) (7x - 6)/2

E) (13x + 3)/2

Can anyone explain using picking numbers approach?

A company hired a printer to produce a total of x + 1 envelopes. The job consisted of two types of envelopes, 2¢ envelopes and 5¢ envelopes. If the company requested 3 more 2¢ envelopes than 5¢ envelopes, which of the following expressions denotes the cost, in cents, of the total x + 1 envelopes ?

A) 3x + 1

B) (7x - 2)/2

C) 11x + 31

D) (7x - 6)/2

E) (13x + 3)/2

Can anyone explain using picking numbers approach?

Let the # of 5¢ envelopes be 2, then # of 2¢ envelopes will be 5, total=2+5=7 envelopes: x+1=7 --> x=6. Cost: 5¢*2+2¢*5=20¢.

Now, plug x=6 in answer choices and see which one gives 20¢:

B. (7x - 2)/2=(7*6-2)/2=20¢. Correct.

Answer: B.

Note that for plug-in method it might happen that for some particular numbers more than one option may give "correct" answer. In this case just pick some other numbers and check again these "correct" options only. For example numbers 1 and 4 gives two "correct" choices A and B.

Re: A company hired a printer to produce a total of x + 1 [#permalink]

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31 May 2013, 06:18

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1

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Let the number of

2c envelopes = p 5c envelopes = q

Given

P = q + 3 P+q=x+1

=> 2q+3 = x+1

Q = x-2/2

Total cost = 2p + 5q substituting p = q+3 we get

= 7q +6 substituting for q

7x - 2/2
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Re: A company hired a printer to produce a total of x + 1 [#permalink]

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31 May 2013, 06:19

3

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Smita04 wrote:

A company hired a printer to produce a total of x + 1 envelopes. The job consisted of two types of envelopes, 2¢ envelopes and 5¢ envelopes. If the company requested 3 more 2¢ envelopes than 5¢ envelopes, which of the following expressions denotes the cost, in cents, of the total x + 1 envelopes ?

A) 3x + 1

B) (7x - 2)/2

C) 11x + 31

D) (7x - 6)/2

E) (13x + 3)/2

Can anyone explain using picking numbers approach?

Assume that no of 5 cents envelopes = 0. Thus, the no of 2 cents envelopes = 3. Total cost = 6 cents. Also, the total no of envelopes,x+1 = 3--> x=2. Only B gives 6 cents for x=2.
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Re: A company hired a printer to produce a total of x + 1 [#permalink]

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10 Jan 2014, 09:36

Smita04 wrote:

A company hired a printer to produce a total of x + 1 envelopes. The job consisted of two types of envelopes, 2¢ envelopes and 5¢ envelopes. If the company requested 3 more 2¢ envelopes than 5¢ envelopes, which of the following expressions denotes the cost, in cents, of the total x + 1 envelopes ?

A) 3x + 1

B) (7x - 2)/2

C) 11x + 31

D) (7x - 6)/2

E) (13x + 3)/2

Can anyone explain using picking numbers approach?

Yeah smart numbers works well here.

X+1 = 7 X= 6

So 2c envelopes will be 5 and 5c envelopes will be 2

Re: A company hired a printer to produce a total of x + 1 [#permalink]

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11 Mar 2015, 06:31

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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A company hired a printer to produce a total of x + 1 [#permalink]

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03 Sep 2015, 10:21

let t=# two cent envelopes let f=# five cent envelopes total cost=2t+5f start with two equations: 1. t+f=x+1 2. t-f=3 adding 1 & 2 ➡ t=(x+4)/2 subtracting 2 from 1 ➡ f=(x-2)/2 substituting in 2t+5f, then 2(x+4/2)+5(x-2/2)=(7x-2)/2

Re: A company hired a printer to produce a total of x + 1 [#permalink]

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03 Oct 2016, 23:34

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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