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A container has 3L of pure wine. 1L from the container is

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Math Expert
Joined: 02 Sep 2009
Posts: 33562
Followers: 5948

Kudos [?]: 73840 [0], given: 9903

Re: A container has 3 liters of pure lime juice. 1 liter from [#permalink]

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04 Oct 2013, 06:54
Expert's post
Cee0612 wrote:
A container has 3 liters of pure lime juice. 1 liter from the container is taken out and 2 liter water is added. The process is repeated several times. After 19 such operations, quantity of lime juice in the mixture is

(A) 2/7 L
(B) 3/7 L
(C) 5/14 L
(D) 5/19 L
(E) 6/19L

Merging similar topics. Please refer to the solutions provided.
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Joined: 06 Dec 2012
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GMAT 1: 510 Q46 V21
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Kudos [?]: 48 [1] , given: 18

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07 Oct 2013, 02:56
1
KUDOS
Bunuel wrote:
Let's go step by step:

First operation: 3L-1L=2=6/3L of wine left, total 4L;
#2: 6/3L-(6/3)/4=6/3-6/12=18/12=6/4L of wine left, total 5L;
#3: 6/4L-(6/4)/5=6/4-6/20=24/20=6/5L, total 6L;
#4: 6/5L-(6/5)/6=6/5-6/30=30/30=6/6L, total 7L;
....

At this point it's already possible to see the pattern: x=6/(n+2)

n=19 --> x=6/(19+2)=6/21=2/7L

1) in 1st operation 1L drawn off. so 2L wine left (6/3L). & added 2L water. so total=4L
2) how come it be 6/4L ?? not getting ?
Re: Ratio and Proportion   [#permalink] 07 Oct 2013, 02:56

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