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Re: A container has red,blue and green balls, and the number of [#permalink]
24 Aug 2013, 06:55

fozzzy wrote:

A container has red,blue and green balls, and the number of green balls is less than 25. How many green balls are in the container? 1) The ratio of red to blue balls is 6 to 5 2) There are twice as many green balls as red balls in the container.

Re: A container has red,blue and green balls, and the number of [#permalink]
24 Aug 2013, 07:04

fameatop wrote:

Statement 1 & 2 Red:Blue = 6:5 Green Balls = 2 x No of Red balls Green Balls = 2 x 6a = 12a We still don't the value of "a". Thus Insufficient

Answer E

Actually we do have the value just that there are 2 sets in this case

Case 1 - Red = 6, blue = 5, Green = 12 Case 2 - Red = 12, Blue = 10, Green = 24

Since statement says Green is below 25 both cases apply. If the question was worded a lil different green less than 15 C would be sufficient! Over here its constraint to be an integer. You can't have 1/2, 1/4 ball so these values won't work _________________

Re: A container has red,blue and green balls, and the number of [#permalink]
27 Dec 2013, 09:17

Statement 1---------------------no info on g so insufficient Statement 2-------------------g=2R but Less than 15 (15 is given as the limit in the original question posted)So maximum value of g can be 14(i.e 2*7),12(2*10),10(2*5),8,6,4,2,

Other values of 15,13,11 i.e Odd values are not possible since we know g=2R and R must be an integer As it represents BALLS so R=1,2,3,4,5 etc etc

Still statement two on its own has too many possible values for g hence insufficient

Combining Statement 1 and statement 2

R:B=6:5

So b=5/6*R and B must be integer so R can Be either 6 or 12 or 18 i.e Multiples of 6

put a table out on all possible values soon we can see that g=12,b=r=6 is the only best fir given all conditions

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