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# A container has red,blue and green balls, and the number of

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Director
Joined: 29 Nov 2012
Posts: 902
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Kudos [?]: 624 [0], given: 543

A container has red,blue and green balls, and the number of [#permalink]  24 Aug 2013, 06:08
00:00

Difficulty:

35% (medium)

Question Stats:

71% (02:08) correct 29% (00:48) wrong based on 52 sessions
A container has red,blue and green balls, and the number of green balls is less than 15. How many green balls are in the container?

1) The ratio of red to blue balls is 6 to 5
2) There are twice as many green balls as red balls in the container.

[Reveal] Spoiler:
I think this question might be sub-600, so not to sure how to tag this one... Edited the question
[Reveal] Spoiler: OA

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Last edited by fozzzy on 24 Aug 2013, 22:56, edited 2 times in total.
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Location: India
Concentration: General Management, Operations
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Kudos [?]: 874 [0], given: 197

Re: A container has red,blue and green balls, and the number of [#permalink]  24 Aug 2013, 06:17
fozzzy wrote:
A container has red,blue and green balls, and the number of green balls is less than 25. How many green balls are in the container?

1) The ratio of red to blue balls is 6 to 5
2) There are twice as many green balls as red balls in the container.

[Reveal] Spoiler:
I think this question might be sub-600, so not to sure how to tag this one...

1) The ratio of red to blue balls is 6 to 5

2) There are twice as many green balls as red balls in the container.
g = 2r
g can take 2,4,6...,24
hence insufficient.

combining
ratio$$\frac{r}{b}$$$$= \frac{6}{5}$$ $$= k$$ (constant)
therefore $$r = 6k$$
$$b= 5k$$
$$g = 12k$$
now we need $$g = 12k<25$$
$$12k<25$$
if$$k = 1 => g = 12$$
if$$k = 2 => g= 24$$
hence again insufficient
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Last edited by blueseas on 24 Aug 2013, 07:10, edited 2 times in total.
Director
Joined: 24 Aug 2009
Posts: 505
Schools: Harvard, Columbia, Stern, Booth, LSB,
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Kudos [?]: 528 [0], given: 241

Re: A container has red,blue and green balls, and the number of [#permalink]  24 Aug 2013, 06:55
fozzzy wrote:
A container has red,blue and green balls, and the number of green balls is less than 25. How many green balls are in the container?
1) The ratio of red to blue balls is 6 to 5
2) There are twice as many green balls as red balls in the container.
[Reveal] Spoiler:
I think this question might be sub-600, so not to sure how to tag this one...

Green balls <25

Statement 1
Red:Blue = 6:5 = 6a:5a
No info about green balls. Thus Insufficient

Statement 2
Green Balls = 2 x No of Red balls
No info about Red balls. Thus Insufficient

Statement 1 & 2
Red:Blue = 6:5
Green Balls = 2 x No of Red balls
Green Balls = 2 x 6a = 12a
We still don't the value of "a". Thus Insufficient

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Director
Joined: 29 Nov 2012
Posts: 902
Followers: 12

Kudos [?]: 624 [0], given: 543

Re: A container has red,blue and green balls, and the number of [#permalink]  24 Aug 2013, 07:04
fameatop wrote:

Statement 1 & 2
Red:Blue = 6:5
Green Balls = 2 x No of Red balls
Green Balls = 2 x 6a = 12a
We still don't the value of "a". Thus Insufficient

Actually we do have the value just that there are 2 sets in this case

Case 1 - Red = 6, blue = 5, Green = 12
Case 2 - Red = 12, Blue = 10, Green = 24

Since statement says Green is below 25 both cases apply. If the question was worded a lil different green less than 15 C would be sufficient! Over here its constraint to be an integer. You can't have 1/2, 1/4 ball so these values won't work
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Intern
Joined: 17 Dec 2013
Posts: 5
Followers: 1

Kudos [?]: 1 [0], given: 1

Re: A container has red,blue and green balls, and the number of [#permalink]  27 Dec 2013, 09:17
Statement 1---------------------no info on g so insufficient
Statement 2-------------------g=2R but Less than 15 (15 is given as the limit in the original question posted)So maximum value of g
can be 14(i.e 2*7),12(2*10),10(2*5),8,6,4,2,

Other values of 15,13,11 i.e Odd values are not possible since we know g=2R and R must be an integer As it represents BALLS so R=1,2,3,4,5 etc etc

Still statement two on its own has too many possible values for g hence insufficient

Combining Statement 1 and statement 2

R:B=6:5

So b=5/6*R and B must be integer so R can Be either 6 or 12 or 18 i.e Multiples of 6

put a table out on all possible values soon we can see that g=12,b=r=6 is the only best fir given all conditions

SVP
Joined: 06 Sep 2013
Posts: 2036
Concentration: Finance
GMAT 1: 770 Q0 V
Followers: 35

Kudos [?]: 394 [0], given: 355

Re: A container has red,blue and green balls, and the number of [#permalink]  10 Jan 2014, 09:52
fozzzy wrote:
A container has red,blue and green balls, and the number of green balls is less than 15. How many green balls are in the container?

1) The ratio of red to blue balls is 6 to 5
2) There are twice as many green balls as red balls in the container.

[Reveal] Spoiler:
I think this question might be sub-600, so not to sure how to tag this one... Edited the question

Statement 1

Doesn't help much cause we don't know anything about green balls

Statement 2

2r = g

Still if r = 1 g = 2
If r=2 g = 4

Statements 1 and 2 together

If r/b = 6/5 then minimum number of red balls is 6 for it to be an integer therefore we have 5 blue balls and 12 green balls

Note that if r = 12 then g would be 24 but we are told that g<15 so this violates one of the givens

C
Re: A container has red,blue and green balls, and the number of   [#permalink] 10 Jan 2014, 09:52
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