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A contractor combined x tons of a gravel mixture that

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Manager
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A contractor combined x tons of a gravel mixture that [#permalink] New post 02 Sep 2009, 01:50
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50% (01:20) correct 50% (00:01) wrong based on 9 sessions
A contractor combined x tons of a gravel mixture that contained 10% gravel G, by weight, with y tons of a mixture that contained 2% gravel G, by weight, to produce z tons of a mixture that was 5% gravel G, by weight. What is the value of x?

1. y = 10
2. z = 16

Answer is D. Can someone please explain how to get to the answer?
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Re: Mixture problem from gmatprep [#permalink] New post 02 Sep 2009, 01:58
x.10%+y.2%=z.5% x+y=z so it makes
x.10%+y.2%=(x+y).5%
x.10%+y.2%=x.5%+y.5%=
x.5%=y.3%
5x=3y
x=3y/5
z=8y/5
so if we know either y or z we can find x.
i.e. 1 and 2 suff, D.
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Re: Mixture problem from gmatprep [#permalink] New post 03 Sep 2009, 21:17
One eq. will be 10x + 2y = 5z

Other eq, x+y=z

Stmt 1 : y =10 ..suff 3 equation...3 variable

Stmt 2 : z = 16 ..suff 3 equation...3 variable
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Re: Mixture problem from gmatprep [#permalink] New post 22 Apr 2011, 22:15
word translation problems requires simplification

and we should not miss to intrept that

z=x+y in this case
:-D :-D :-D
then simplified equation will be 5x=3y and z=x+y

:arrow: hence both staement are sufficent D
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lets start again

Re: Mixture problem from gmatprep   [#permalink] 22 Apr 2011, 22:15
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