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A costs 30 per kg. B costs 20 per kg. A blend of A and B

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CEO
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A costs 30 per kg. B costs 20 per kg. A blend of A and B [#permalink] New post 20 Dec 2007, 21:11
A costs 30 per kg.
B costs 20 per kg.
A blend of A and B costs 22 per kg.
What is the percentage of B in the blend?
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 [#permalink] New post 20 Dec 2007, 22:50
say the value is x.

then u get:

(1-x)*30 + x*20 = 22.

solve x.
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Re: blend [#permalink] New post 20 Dec 2007, 23:26
bmwhype2 wrote:
A costs 30 per kg.
B costs 20 per kg.
A blend of A and B costs 22 per kg.
What is the percentage of B in the blend?


A: x kg Cost = 30x

B: y kg Cost= 20y

(A+B): (x+y) kg Cost = 22(x+y)

30x +20y = 22(x+y)

4x = y

y/(x+y) = 4x/(5x) = (4/5)*100 = 80%
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 [#permalink] New post 23 Dec 2007, 03:57
very nice. OA is 80%
  [#permalink] 23 Dec 2007, 03:57
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A costs 30 per kg. B costs 20 per kg. A blend of A and B

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