SravnaTestPrep wrote:

A cube is made up of equal smaller cubes. Two of the sides of the larger cube are called A and B. What is the total number of smaller cubes?

(1) When n smaller cubes are painted on A , n is 1/9 of the total number of smaller cubes.

(2) When m smaller cubes are painted on B, m is 1/3 of the total number of smaller cubes

Fact 1: When a cube is made of equal smaller cubes, the number of smaller cubes is \(r^3\) where r is natural number.

Fact 2: Out of the six sides of the bigger cube, we are considering two sides and have named them A and B resp.

Statement 1: when on side A, n smaller cubes are painted we have that value of n equal to 1/9 of the total number of smaller cubes. So n is divisible by 9. Or the number of smaller cubes is a multiple of 9. Statement is not sufficient to answer the question because for example both 27 smaller cubes and 729 smaller cubes satisfy the conditions that the number of smaller cubes is a multiple of 9 and satisfies fact 1.

Statement 2: In this case the number of smaller cubes is a multiple of 3. The number of smaller cubes cannot be greater than \(3^3\) based on this statement alone.

Assume first the number of smaller cubes which is a multiple of 3 and satisfies fact 1, is 27.

In this case each side has 9 smaller cubes exposed. If the number of smaller cubes painted, which is m, is 9.we have m =1/3 of the number of smaller cubes.

Assume next the the number of smaller cubes which is a multiple of 3 and satisfies fact 1, is 216.

In this case each side has 36 smaller cubes exposed. So you could paint a maximum of 36 smaller cubes. Thus maximum value of m is 36/216 = 1/6 which cannot be equal to 1/3.

For higher multiples of 3, the value of m would keep on decreasing and would never satisfy the conditions mentioned.

Thus statement 2 alone is sufficient to answer this question.

Therefore answer is choice B.

Sorry to point this out but something here is leading to confusion.

First of all if n is the total number of smaller cubes then each surface would have n/6 cubes exposed. This is what I derive from the green highlighted text where it says if 216 is total number of cubes then each surface would have 36 exposed which means we are doing 216/6= 36

By the same logic if 27 is the total number of smaller cubes then each side should have 27/6 number of cubes exposed which means 4.5cubes.

so you can paint a maximum of 4.5 cubes.

(So how come you say that for 27 total number of smaller cubes each side would have 9 cubes exposed?shouldn't it be 27/6 as you did for 216/6)

4.5/27= 1/6 , this is what we were getting for 216 cubes too!, so we cannot have 1/3 hence it seems that even 27 total smaller cubes is not a possibility.

Please let me know if I have not understood something.