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# A cuboid pool, when it is half full, the water level height

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A cuboid pool, when it is half full, the water level height [#permalink]  14 Apr 2006, 17:49
A cuboid pool, when it is half full, the water level height is (Let it be H). If drain out 500 liters of water, the level is (Let it be h). What is volume of the pool?
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Is it 250*H/(H-h)?
Senior Manager
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1000H/(H-h)

- Vipin
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Got that one wrong... Vipin is right.

If A is cross-sectional area, and V is volume:

AH=1/2*V (had this eqn the other way round in my calcs )
HA-hA=500

Thanks Vipin...
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vipin7um wrote:
1000H/(H-h)

- Vipin

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Volume of the pool = lb(2H) (assume l is length and b is breadth)

After draining:

500 = lb(H-h)

or lb = 500/(H-h)

substituting lb in the first eq

Volume = 1000H/(H-h)
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M8 wrote:
vipin7um wrote:
1000H/(H-h)

- Vipin

Hi M8,
Let us say the area is A.

=> V = A * 2H - (1)

Also 500 ltr of water reduces the hight from H to h

=> 500 = A * (H-h) - (2)

Solving (1) and (2) for A gives the Volume.

HTH...
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