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A cuboid pool, when it is half full, the water level height

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A cuboid pool, when it is half full, the water level height [#permalink] New post 14 Apr 2006, 17:49
A cuboid pool, when it is half full, the water level height is (Let it be H). If drain out 500 liters of water, the level is (Let it be h). What is volume of the pool?
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 [#permalink] New post 14 Apr 2006, 18:08
Is it 250*H/(H-h)?
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 [#permalink] New post 14 Apr 2006, 18:31
1000H/(H-h)

- Vipin
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 [#permalink] New post 14 Apr 2006, 19:09
Got that one wrong... Vipin is right.

If A is cross-sectional area, and V is volume:

AH=1/2*V (had this eqn the other way round in my calcs :x )
HA-hA=500
Eliminate A for the answer.

Thanks Vipin...
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 [#permalink] New post 15 Apr 2006, 00:49
vipin7um wrote:
1000H/(H-h)

- Vipin


Vipin please elaborate it.
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 [#permalink] New post 15 Apr 2006, 01:06
Volume of the pool = lb(2H) (assume l is length and b is breadth)

After draining:

500 = lb(H-h)

or lb = 500/(H-h)


substituting lb in the first eq

Volume = 1000H/(H-h)
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 [#permalink] New post 15 Apr 2006, 07:52
M8 wrote:
vipin7um wrote:
1000H/(H-h)

- Vipin


Vipin please elaborate it.


Hi M8,
Let us say the area is A.

=> V = A * 2H - (1)

Also 500 ltr of water reduces the hight from H to h

=> 500 = A * (H-h) - (2)

Solving (1) and (2) for A gives the Volume.

HTH...
  [#permalink] 15 Apr 2006, 07:52
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