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# A dairy man pays $6.4 per litre of milk; he adds water and  Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: Director Joined: 13 Nov 2003 Posts: 790 Location: BULGARIA Followers: 1 Kudos [?]: 30 [0], given: 0 A dairy man pays$ 6.4 per litre of milk; he adds water and [#permalink]  23 Mar 2004, 00:57
A dairy man pays $6.4 per litre of milk; he adds water and sells the mixture at$ 8 per litre, thereby making 37.5% profit. Find the
proportion of water to milk received by the customers.

1) 1 : 15
2) 1 : 10
3) 1 : 20
4) 1 : 12
Senior Manager
Joined: 02 Mar 2004
Posts: 328
Location: There
Followers: 1

Kudos [?]: 0 [0], given: 0

$0-------------------------------$64/11-----------------------------$6.4 (64/10)-(64/11) = 64/110 64/11 - 0 = 64/11 64/110 : 64/11 = 1:10 Director Joined: 13 Nov 2003 Posts: 790 Location: BULGARIA Followers: 1 Kudos [?]: 30 [0], given: 0 [#permalink] 23 Mar 2004, 11:19 halle, I bow before you. Perfect. SVP Joined: 30 Oct 2003 Posts: 1794 Location: NewJersey USA Followers: 5 Kudos [?]: 43 [0], given: 0 [#permalink] 23 Mar 2004, 13:23 8*(m+w) = 1.375 * 6.4 * m 8w = m( 6.4 * (1.25 + 0.125) - 8 ) w/m = 0.8(1.25+0.125) - 1 = 0.1 so w:m = 1:10 I was trying not to solve quant problems for some time and concentrate on verbal. But kpadma dragged me into this. I think it is all about addiction. I wanr everyone about this addiction and suggest concentrating on certain known weak points. GMAT Club Legend Joined: 15 Dec 2003 Posts: 4309 Followers: 29 Kudos [?]: 235 [0], given: 0 [#permalink] 23 Mar 2004, 13:54 Just to add my approach. Price you would have to sell at in order to get 37.5% profit: 1.375*6.4$ = 8.8$In order for you to still keep a 37.5% profit while selling the diluted milk at 8$, then the .8$difference must represent the water proportion. Then water to milk: .8$ / 8$= 1 : 10 _________________ Best Regards, Paul Director Joined: 03 Jul 2003 Posts: 654 Followers: 2 Kudos [?]: 32 [0], given: 0 [#permalink] 23 Mar 2004, 14:37 anandnk wrote: But kpadma dragged me into this. I think it is all about addiction. I wanr everyone about this addiction and suggest concentrating on certain known weak points. Well, What can I say. I'm an addict, now! Here is another method! Customer gets 1 liter for$8
Vender pays (1-x)*$6.4 for that adulterated 1 liter milk and makes 37.5% profit. Where X = water in 1 liter adulterated milk 6.4(1-x) * 1.375 = 8 Solve for X, we get 1/11. Pure milk in 1 liter adultrated milk is 10/11 W:M = 1/11 : 10/11 = 1:10 Well, time for another round [#permalink] 23 Mar 2004, 14:37 Similar topics Replies Last post Similar Topics: 4 A vessel contains milk and water in the ratio 3:2 5 26 Sep 2011, 09:49 A certain farmer pays$30 per acre per month to rent 8 08 Apr 2008, 11:33
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