ju_1 wrote:

A diet contains 300 grams of a mixture of two foods, food X and food Y. Food X contains 10 percent protein and food Y contains 15 percent protein. If a diet provides exactly 38 grams of protein daily, how many grams of food X are in the mixture?

(A) 150

(B)145

(C) 100

(D) 160

(E) 140

x(10%) y(15%)

38%

23% 28%

the protein parts in the final mixture for X:Y::23:28

hence

23 X

----------- = --------------

(23+28) 300

23/51 = x/300

x = 23 * 300

------------

51

hence x is approximately equal to 139.8

hence the answer is E

_________________

Regards,

Harsha

Note: Give me kudos if my approach is right , else help me understand where i am missing.. I want to bell the GMAT Cat

Satyameva Jayate - Truth alone triumphs