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A division of a company consists of seven men and five women [#permalink]
08 Jan 2013, 09:42

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A

B

C

D

E

Difficulty:

5% (low)

Question Stats:

88% (01:56) correct
12% (01:25) wrong based on 136 sessions

A division of a company consists of seven men and five women. If two of these twelve employees are randomly selected as representatives of the division, what is the probability that both representatives will be female? (A) 1/6 (B) 2/5 (C) 2/9 (D) 5/12 (E) 5/33

Re: A division of a company consists of seven men and five women [#permalink]
09 Jan 2013, 06:44

1

This post was BOOKMARKED

Total number of ways to select 2 members from 12 members = 12C2 - denominator Total number of ways to select 2 females from 5 total females = 5C2 - numerator

Therefore probability of having 2 females reps is 5C2 / 12C2 = 5/33 (E)

Re: A division of a company consists of seven men and five women [#permalink]
09 Jan 2013, 18:56

A different way.

There are a total of 12 employees (7 men and 5 women)

Probability of 1st person selected being a woman is 5/12 Probability of the 2nd person selected being a woman is 4/11 (4 women left in the 11 remaining employees)

Probability of 1st and 2nd selected both being women =5/12 X 4/11 = 20/132 which reduces to = 5/33

Re: A division of a company consists of seven men and five women [#permalink]
19 Sep 2014, 10:29

holidayhero wrote:

A different way.

There are a total of 12 employees (7 men and 5 women)

Probability of 1st person selected being a woman is 5/12 Probability of the 2nd person selected being a woman is 4/11 (4 women left in the 11 remaining employees)

Probability of 1st and 2nd selected both being women =5/12 X 4/11 = 20/132 which reduces to = 5/33

Answer E

Hello, why don't we multiply the final answer with 2? Because there are two ways in which we can accomplish this.

The reason we don't have to multiply by two in the solution is because we are drawing from the same pool. In the example you are thinking (http://gmatclub.com/forum/john-has-on-his-shelf-four-books-of-poetry-145499.html), there are two different pools to choose from, novels and reference. In this case, the only pool we're picking from is the pool of women. Of the two picks, we want the first to be a woman, and the second to be a woman. There is no way to "flip" this selection, as the "flip" is the same as our original scenario. In the other problem, the reason we have to multiply by two is because we have two outcomes, the first selection is a novel and the second is a reference, or the first is a reference and the second is a novel.

The reason we don't have to multiply by two in the solution is because we are drawing from the same pool. In the example you are thinking (http://gmatclub.com/forum/john-has-on-his-shelf-four-books-of-poetry-145499.html), there are two different pools to choose from, novels and reference. In this case, the only pool we're picking from is the pool of women. Of the two picks, we want the first to be a woman, and the second to be a woman. There is no way to "flip" this selection, as the "flip" is the same as our original scenario. In the other problem, the reason we have to multiply by two is because we have two outcomes, the first selection is a novel and the second is a reference, or the first is a reference and the second is a novel.

Re: A division of a company consists of seven men and five women [#permalink]
05 Jul 2015, 02:47

Hi everyone, here's my solution for Example 2: We have 7 males + 5 females = 12

The probability that the first choice will be a woman is 5/12 (females/all) The probability that the second choice will be a woman is 4/11 (for the second run we have 4 women and 11 Persons left)

5/12*4/11 = 5/33 _________________

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Re: A division of a company consists of seven men and five women
[#permalink]
05 Jul 2015, 02:47

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