Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

89% (01:52) correct
11% (02:06) wrong based on 159 sessions

HideShow timer Statistics

A division of a company consists of seven men and five women. If two of these twelve employees are randomly selected as representatives of the division, what is the probability that both representatives will be female? (A) 1/6 (B) 2/5 (C) 2/9 (D) 5/12 (E) 5/33

Re: A division of a company consists of seven men and five women [#permalink]

Show Tags

09 Jan 2013, 07:44

1

This post was BOOKMARKED

Total number of ways to select 2 members from 12 members = 12C2 - denominator Total number of ways to select 2 females from 5 total females = 5C2 - numerator

Therefore probability of having 2 females reps is 5C2 / 12C2 = 5/33 (E)

Re: A division of a company consists of seven men and five women [#permalink]

Show Tags

09 Jan 2013, 19:56

A different way.

There are a total of 12 employees (7 men and 5 women)

Probability of 1st person selected being a woman is 5/12 Probability of the 2nd person selected being a woman is 4/11 (4 women left in the 11 remaining employees)

Probability of 1st and 2nd selected both being women =5/12 X 4/11 = 20/132 which reduces to = 5/33

Re: A division of a company consists of seven men and five women [#permalink]

Show Tags

19 Sep 2014, 11:29

holidayhero wrote:

A different way.

There are a total of 12 employees (7 men and 5 women)

Probability of 1st person selected being a woman is 5/12 Probability of the 2nd person selected being a woman is 4/11 (4 women left in the 11 remaining employees)

Probability of 1st and 2nd selected both being women =5/12 X 4/11 = 20/132 which reduces to = 5/33

Answer E

Hello, why don't we multiply the final answer with 2? Because there are two ways in which we can accomplish this.

The reason we don't have to multiply by two in the solution is because we are drawing from the same pool. In the example you are thinking (http://gmatclub.com/forum/john-has-on-his-shelf-four-books-of-poetry-145499.html), there are two different pools to choose from, novels and reference. In this case, the only pool we're picking from is the pool of women. Of the two picks, we want the first to be a woman, and the second to be a woman. There is no way to "flip" this selection, as the "flip" is the same as our original scenario. In the other problem, the reason we have to multiply by two is because we have two outcomes, the first selection is a novel and the second is a reference, or the first is a reference and the second is a novel.

The reason we don't have to multiply by two in the solution is because we are drawing from the same pool. In the example you are thinking (http://gmatclub.com/forum/john-has-on-his-shelf-four-books-of-poetry-145499.html), there are two different pools to choose from, novels and reference. In this case, the only pool we're picking from is the pool of women. Of the two picks, we want the first to be a woman, and the second to be a woman. There is no way to "flip" this selection, as the "flip" is the same as our original scenario. In the other problem, the reason we have to multiply by two is because we have two outcomes, the first selection is a novel and the second is a reference, or the first is a reference and the second is a novel.

Re: A division of a company consists of seven men and five women [#permalink]

Show Tags

05 Jul 2015, 03:47

Hi everyone, here's my solution for Example 2: We have 7 males + 5 females = 12

The probability that the first choice will be a woman is 5/12 (females/all) The probability that the second choice will be a woman is 4/11 (for the second run we have 4 women and 11 Persons left)

5/12*4/11 = 5/33
_________________

When you’re up, your friends know who you are. When you’re down, you know who your friends are.

Share some Kudos, if my posts help you. Thank you !

After days of waiting, sharing the tension with other applicants in forums, coming up with different theories about invites patterns, and, overall, refreshing my inbox every five minutes to...

I was totally freaking out. Apparently, most of the HBS invites were already sent and I didn’t get one. However, there are still some to come out on...

In early 2012, when I was working as a biomedical researcher at the National Institutes of Health , I decided that I wanted to get an MBA and make the...