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A drives at a rate of m miles per hour from his home to the

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A drives at a rate of m miles per hour from his home to the [#permalink] New post 26 Aug 2010, 18:33
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Question Stats:

82% (02:34) correct 18% (03:35) wrong based on 92 sessions
A drives at a rate of m miles per hour from his home to the park. On his return trip he drives at a rate of n miles per hour. How far away from his home is the part if he spends a total of z hours in the car, making no stops along the way?

A. \frac{n+z}{m}-\frac{z}{n}

B. \frac{m+n+z}{mn}

C. \frac{mnz}{m+n}

D. \frac{m+z}{mn}

E. \frac{mz}{n}
[Reveal] Spoiler: OA

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Last edited by Bunuel on 19 Apr 2012, 19:58, edited 1 time in total.
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Re: Rate --- GMAT Practice Question. [#permalink] New post 26 Aug 2010, 19:05
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ezhilkumarank wrote:
Question: A drives at a rate of m miles per hour from his home to the park. On his return trip he drives at a rate of n miles per hour. How far away from his home is the part if he spends a total of z hours in the car, making no stops along the way?

A) ((n+z)/m) - (z/n)
B) (m+n+z)/mn
C) (mnz)/(m+n)
D) (m+z)/mn
E) mz/n


Let the distance between home and park be d.

From home to park A would need \frac{d}{m} hours and from park to home A would need \frac{d}{n} hours as A spent total of z hours for round trip then \frac{d}{m}+\frac{d}{n}=z --> d(\frac{m+n}{mn})=z --> d=\frac{mnz}{m+n}.

Answer: C.
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Senior Manager
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Status: Time to step up the tempo
Joined: 24 Jun 2010
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Re: Rate --- GMAT Practice Question. [#permalink] New post 26 Aug 2010, 21:49
Bunuel wrote:
ezhilkumarank wrote:
Question: A drives at a rate of m miles per hour from his home to the park. On his return trip he drives at a rate of n miles per hour. How far away from his home is the part if he spends a total of z hours in the car, making no stops along the way?

A) ((n+z)/m) - (z/n)
B) (m+n+z)/mn
C) (mnz)/(m+n)
D) (m+z)/mn
E) mz/n


Let the distance between home and park be d.

From home to park A would need \frac{d}{m} hours and from park to home A would need \frac{d}{n} hours as A spent total of z hours for round trip then \frac{d}{m}+\frac{d}{n}=z --> d(\frac{m+n}{mn})=z --> d=\frac{mnz}{m+n}.

Answer: C.


Bunuel -- you made it look so simple. I could not get my mind cranked up so quickly. Guess I have to practice more. :-D
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Re: A drives at a rate of m miles per hour from his home to the [#permalink] New post 30 Jun 2014, 09:22
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Re: A drives at a rate of m miles per hour from his home to the   [#permalink] 30 Jun 2014, 09:22
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