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A drives at a rate of m miles per hour from his home to the

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A drives at a rate of m miles per hour from his home to the [#permalink] New post 26 Aug 2010, 18:33
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Question Stats:

81% (02:38) correct 19% (02:51) wrong based on 129 sessions
A drives at a rate of m miles per hour from his home to the park. On his return trip he drives at a rate of n miles per hour. How far away from his home is the part if he spends a total of z hours in the car, making no stops along the way?

A. \(\frac{n+z}{m}-\frac{z}{n}\)

B. \(\frac{m+n+z}{mn}\)

C. \(\frac{mnz}{m+n}\)

D. \(\frac{m+z}{mn}\)

E. \(\frac{mz}{n}\)
[Reveal] Spoiler: OA

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Last edited by Bunuel on 19 Apr 2012, 19:58, edited 1 time in total.
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Re: Rate --- GMAT Practice Question. [#permalink] New post 26 Aug 2010, 19:05
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ezhilkumarank wrote:
Question: A drives at a rate of m miles per hour from his home to the park. On his return trip he drives at a rate of n miles per hour. How far away from his home is the part if he spends a total of z hours in the car, making no stops along the way?

A) \(((n+z)/m) - (z/n)\)
B) \((m+n+z)/mn\)
C) \((mnz)/(m+n)\)
D) \((m+z)/mn\)
E) \(mz/n\)


Let the distance between home and park be \(d\).

From home to park A would need \(\frac{d}{m}\) hours and from park to home A would need \(\frac{d}{n}\) hours as A spent total of z hours for round trip then \(\frac{d}{m}+\frac{d}{n}=z\) --> \(d(\frac{m+n}{mn})=z\) --> \(d=\frac{mnz}{m+n}\).

Answer: C.
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Senior Manager
Senior Manager
User avatar
Status: Time to step up the tempo
Joined: 24 Jun 2010
Posts: 408
Location: Milky way
Schools: ISB, Tepper - CMU, Chicago Booth, LSB
Followers: 7

Kudos [?]: 146 [0], given: 50

Re: Rate --- GMAT Practice Question. [#permalink] New post 26 Aug 2010, 21:49
Bunuel wrote:
ezhilkumarank wrote:
Question: A drives at a rate of m miles per hour from his home to the park. On his return trip he drives at a rate of n miles per hour. How far away from his home is the part if he spends a total of z hours in the car, making no stops along the way?

A) \(((n+z)/m) - (z/n)\)
B) \((m+n+z)/mn\)
C) \((mnz)/(m+n)\)
D) \((m+z)/mn\)
E) \(mz/n\)


Let the distance between home and park be \(d\).

From home to park A would need \(\frac{d}{m}\) hours and from park to home A would need \(\frac{d}{n}\) hours as A spent total of z hours for round trip then \(\frac{d}{m}+\frac{d}{n}=z\) --> \(d(\frac{m+n}{mn})=z\) --> \(d=\frac{mnz}{m+n}\).

Answer: C.


Bunuel -- you made it look so simple. I could not get my mind cranked up so quickly. Guess I have to practice more. :-D
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Re: A drives at a rate of m miles per hour from his home to the [#permalink] New post 30 Jun 2014, 09:22
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Re: A drives at a rate of m miles per hour from his home to the [#permalink] New post 01 Sep 2015, 06:09
Hello from the GMAT Club BumpBot!

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Re: A drives at a rate of m miles per hour from his home to the   [#permalink] 01 Sep 2015, 06:09
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