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A factory producing tennis balls stores them in either big [#permalink]
 27 May 2008, 22:17
Question Stats:
46% (01:56) correct
53% (01:13) wrong based on 8 sessions
A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 17 balls per box. If 95 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed? A. 1 B. 2 C. 3 D. 4 E. 5
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Re: M18-5-find the quickest way [#permalink]
27 May 2008, 22:27
sondenso wrote: A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 17 balls per box. If 95 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed?
1
2
3
4
5 25*3 + 17 = 92 so C.3 should be the answer
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Re: M18-5-find the quickest way [#permalink]
27 May 2008, 22:37
I think we can put that as 25X1+17X4=93 hence 2 is the answer ; I tried by checking for 94, 93 from the answer options and think is the quickest (took 1 min)
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Re: M18-5-find the quickest way [#permalink]
27 May 2008, 22:39
alpha_plus_gamma wrote: sondenso wrote: A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 17 balls per box. If 95 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed?
1
2
3
4
5 25*3 + 17 = 92 so C.3 should be the answer I think the answer is B - 2. 25*1 + 17*4 = 93. I don't think there's an quick way example plug in numbers starting with multiples of 25.
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Re: M18-5-find the quickest way [#permalink]
27 May 2008, 22:41
lucyqin wrote: alpha_plus_gamma wrote: sondenso wrote: A factory producing tennis balls stores them in either big boxes, 25 balls per box, or small boxes, 17 balls per box. If 95 freshly manufactured balls are to be stored, what is the least number of balls that can be left unboxed?
1
2
3
4
5 25*3 + 17 = 92 so C.3 should be the answer I think the answer is B - 2. 25*1 + 17*4 = 93. I don't think there's an quick way example plug in numbers starting with multiples of 25. yes B should be right, my mistake!
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Re: M18-5-find the quickest way [#permalink]
27 May 2008, 22:42
why not 0
the question does not state that the boxes have to be full.
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Re: M18-5-find the quickest way [#permalink]
28 May 2008, 00:16
Thanks all, Oa is B alpha_plus_gamma wrote: 25*3 + 17 = 92 so C.3 should be the answer In theory, I think maximum 3 times 25, and then force times of 17 as above. But this question does not follow the theory? What do you think? Thanks!
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Re: M18-5-find the quickest way [#permalink]
28 May 2008, 10:58
gmatnub wrote: why not 0
the question does not state that the boxes have to be full. I agree, this question is worded horribly. You could fill the 75 balls into 3 of the large boxes and then put the remaining 20 balls into another large box and still have room for 5 more balls. Answer should be zero. Now, if they asked what is the least number of boxes that could be used, that would make more sense.
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Re: M18-5-find the quickest way [#permalink]
28 May 2008, 12:27
B
We have to work with multiples of 17 and 25.
First, we must know the limits of this multiples, so:
95/25= 3....so the max is 3
95/17=5...so the max is 5
If we have 3 boxes of 25 (75 u1) and 1 box of 17 (75+17=92) we have 3 balls out. (95-92)
This is a trap, because as I said before we must work with
17 25
34 50
51 75
68 100
85
102 NOT
Here, you can see that 68+25=93, so we have 2 balls out, so B.
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Re: A factory producing tennis balls stores them in either big [#permalink]
21 Feb 2013, 06:26
Do we have any algebraic soln to this ? It took me 2:29 mins to solve this by plugging in numbers and testing cases?
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Re: A factory producing tennis balls stores them in either big
[#permalink]
21 Feb 2013, 06:26
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