kidboc1 wrote:

A five-member committee is to be formed from a group of five military officers and nine civilians. If the committee must include at least two officers and two civilians, in how many different ways can the committee be chosen?

answer is 1,200

Could someone please assist in the methodology of answering this?

thanks

Remember this -> When you have AND you MULTIPLY and when you have OR, you ADD

CASE1 -> we choose 3 out of 5 military officials

AND 2 out of 9 civilians => 5C3 * 9C2

ORCASE2 -> we choose 2 out of 5 military officials

AND 3 out of 9 civilians => 5C2 * 9C3

So here CASE1 OR CASE2 = > 5C3*9C2 + 5C2*9C3 = 1200

Hope that helps

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