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A florist has 2 azaleas, 3 buttercups, and 4 petunias. She [#permalink]
22 Jan 2011, 08:25

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Difficulty:

45% (medium)

Question Stats:

70% (02:34) correct
30% (01:48) wrong based on 62 sessions

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?

Re: Probability ..tough one [#permalink]
22 Jan 2011, 08:34

1

This post received KUDOS

Expert's post

ajit257 wrote:

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts 2 flowers together at random in a bouquet. However customer calls and says she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet ?

Let's count the probability of the opposite event and subtract it from 1. Opposite event would be that the florist made a bouquet with two of the same flower: \(\frac{C^2_2+C^2_3+C^2_4}{C^2_{9}}=\frac{10}{36}\) --> \(P=1-\frac{10}{36}=\frac{26}{36}=\frac{13}{18}\)

Re: Probability ..tough one [#permalink]
05 Feb 2011, 09:21

1

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total possibilities of selecting 2 flowers from 9 = 9*8= 72 position doesn't matter i.e. {AB} & {BA} mean the same. so total cases = \(\frac{72}{2} = 36\)

Florist 2azaleas, 3 buttercups and 4 petunias [#permalink]
16 Nov 2012, 19:19

dimri10 wrote:

2 azaleas, 3 buttercups, and 4 petunias for total of 9: same flower: 2 azaleas- 2/9*1/8 of choosing the same flower. 3 buttercups- 3/9*2/8 4 petunias - 4/9*3/8 2/72+6/72+12/72=20/72 Probability to chhose the same flower.

we want the probability of not choosing so 1-20/72=52/72=26/36=13/18

Would someone please explain why do we multiply by 1/8, 2/8, 3/8?

Pls help with explanation for this problem from MGMAT Strategy Guide 5 [#permalink]
01 Sep 2014, 22:28

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?

Re: A florist has 2 azaleas, 3 buttercups, and 4 petunias. She [#permalink]
02 Sep 2014, 02:09

Expert's post

arpshriv wrote:

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?

Merging similar tropics. please refer to the discussion above.

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