Live Q&A Session with HKU Admissions Team | Join the chat room to participate.

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She [#permalink]
22 Jan 2011, 08:25

00:00

A

B

C

D

E

Difficulty:

55% (hard)

Question Stats:

69% (02:37) correct
31% (01:48) wrong based on 58 sessions

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?

Re: Probability ..tough one [#permalink]
22 Jan 2011, 08:34

1

This post received KUDOS

Expert's post

ajit257 wrote:

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts 2 flowers together at random in a bouquet. However customer calls and says she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet ?

Let's count the probability of the opposite event and subtract it from 1. Opposite event would be that the florist made a bouquet with two of the same flower: \frac{C^2_2+C^2_3+C^2_4}{C^2_{9}}=\frac{10}{36} --> P=1-\frac{10}{36}=\frac{26}{36}=\frac{13}{18}

Florist 2azaleas, 3 buttercups and 4 petunias [#permalink]
16 Nov 2012, 19:19

dimri10 wrote:

2 azaleas, 3 buttercups, and 4 petunias for total of 9: same flower: 2 azaleas- 2/9*1/8 of choosing the same flower. 3 buttercups- 3/9*2/8 4 petunias - 4/9*3/8 2/72+6/72+12/72=20/72 Probability to chhose the same flower.

we want the probability of not choosing so 1-20/72=52/72=26/36=13/18

Would someone please explain why do we multiply by 1/8, 2/8, 3/8?

Pls help with explanation for this problem from MGMAT Strategy Guide 5 [#permalink]
01 Sep 2014, 22:28

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?

Re: A florist has 2 azaleas, 3 buttercups, and 4 petunias. She [#permalink]
02 Sep 2014, 02:09

Expert's post

arpshriv wrote:

A florist has 2 azaleas, 3 buttercups, and 4 petunias. She puts two flowers together at random in a bouquet. However, the customer calls and says that she does not want two of the same flower. What is the probability that the florist does not have to change the bouquet?

Merging similar tropics. please refer to the discussion above.

Hey everyone, today’s post focuses on the interview process. As I get ready for interviews at Kellogg and Tuck (and TheEngineerMBA ramps up for his HBS... ...