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A group of 8 friends want to play doubles tennis. How many

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Manager
Manager
Status: ISB, Hyderabad
Joined: 25 Jul 2010
Posts: 177
WE 1: 4 years Software Product Development
WE 2: 3 years ERP Consulting
Followers: 4

Kudos [?]: 19 [0], given: 15

Re: combination [#permalink] New post 17 Oct 2010, 19:11
E. I used the formula and got 8!/(2!2!2!2!)*4!
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Manager
Manager
Joined: 08 Oct 2010
Posts: 216
Location: Uzbekistan
Schools: Johnson, Fuqua, Simon, Mendoza
WE 3: 10
Followers: 7

Kudos [?]: 104 [0], given: 974

GMAT Tests User
Re: combination [#permalink] New post 18 Jan 2011, 10:52
There is a proper formula to calculate this: (mn!/(n!)^m)*(1/m!)
According to the question stem --> mn=8; m=4; n=2
Hence --> (8!/(2!)^4)*(1/4!)=105
The Ans. is E
Senior Manager
Senior Manager
Joined: 20 Dec 2010
Posts: 261
Schools: UNC Duke Kellogg
Followers: 3

Kudos [?]: 18 [0], given: 4

GMAT Tests User
Re: combination [#permalink] New post 01 Jul 2011, 21:35
Nice question!....great explanations from Bunuel...
Re: combination   [#permalink] 01 Jul 2011, 21:35
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