Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 03 May 2015, 15:02

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A group of four women and three men have tickets for seven

Author Message
TAGS:
VP
Joined: 10 Jun 2007
Posts: 1465
Followers: 6

Kudos [?]: 133 [0], given: 0

A group of four women and three men have tickets for seven [#permalink]  15 Aug 2007, 18:17
A group of four women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?

(A) 7! – 2!3!2!
(B) 7! – 4!3!
(C) 7! – 5!3!
(D) 7 × 2!3!2!
(E) 2!3!2!
Director
Joined: 11 Jun 2007
Posts: 932
Followers: 1

Kudos [?]: 70 [0], given: 0

Re: Theater Seats [#permalink]  15 Aug 2007, 19:45
bkk145 wrote:
A group of four women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?

(A) 7! – 2!3!2!
(B) 7! – 4!3!
(C) 7! – 5!3!
(D) 7 × 2!3!2!
(E) 2!3!2!

going to try to work it out even though I am probably wrong
different possibilities - we know that the men and women will alternate seats since men will not sit next to each other
1) M W M W M W W

2) W M W M W M W

3) W W M W M W M

I think the answer is E
Director
Joined: 03 May 2007
Posts: 894
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 63 [0], given: 7

Re: Theater Seats [#permalink]  15 Aug 2007, 21:02
bkk145 wrote:
A group of four women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?

(A) 7! – 2!3!2!
(B) 7! – 4!3!
(C) 7! – 5!3!
(D) 7 × 2!3!2!
(E) 2!3!2!

C.
= 7! - 6x5x4!
= 7! - 6!
= 7! - 5!3x2
= 7! - 5!3!
Manager
Joined: 08 Oct 2006
Posts: 215
Followers: 1

Kudos [?]: 5 [0], given: 0

Re: Theater Seats [#permalink]  15 Aug 2007, 22:00
Fistail wrote:
bkk145 wrote:
A group of four women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?

(A) 7! – 2!3!2!
(B) 7! – 4!3!
(C) 7! – 5!3!
(D) 7 × 2!3!2!
(E) 2!3!2!

C.
= 7! - 6x5x4!
= 7! - 6!
= 7! - 5!3x2
= 7! - 5!3!

can you explain this bit.

my way is
total ways =7!
ways that men can sit together with women=5! ways. considering men as a single seat.
3!= no. of ways men can sit together.

So 7!- 5!.3!.
Director
Joined: 03 May 2007
Posts: 894
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 63 [0], given: 7

Re: Theater Seats [#permalink]  16 Aug 2007, 06:37
excelgmat wrote:
Fistail wrote:
bkk145 wrote:
A group of four women and three men have tickets for seven adjacent seats in one row of a theatre. If the three men will not sit in three adjacent seats, how many possible different seating arrangements are there for these 7 theatre-goers?

(A) 7! – 2!3!2!
(B) 7! – 4!3!
(C) 7! – 5!3!
(D) 7 × 2!3!2!
(E) 2!3!2!

C.
= 7! - 6x5x4!
= 7! - 6!
= 7! - 5!3x2
= 7! - 5!3!

can you explain this bit.

my way is
total ways =7!
ways that men can sit together with women=5! ways. considering men as a single seat.
3!= no. of ways men can sit together.

So 7!- 5!.3!.

required = total - 3 men adjecent

total = 7!
3 men adjacent to each other can be placed in 5 places = 5
3 men can be placed adjacent to each other in a place = 3! = 3x2 = 6 ways
remaining 4 people can be placed = 4! ways

so, required = 7! - 6x5x4! = 7! - 6! = 7! - 5!3!
Re: Theater Seats   [#permalink] 16 Aug 2007, 06:37
Similar topics Replies Last post
Similar
Topics:
5 Four men and three women make up a seven-member committee 6 14 Jul 2013, 11:12
7 Seven men and seven women have to sit around a circular 10 07 Apr 2010, 15:10
15 A group of four women and three men have tickets for seven a 10 30 Dec 2009, 20:43
Seven men and seven women have to sit around a circular 3 23 Oct 2006, 10:04
Seven men and seven women have to sit around a circular 3 12 Oct 2006, 11:06
Display posts from previous: Sort by