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A group of men and women competed in a marathon. Before the

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VP
VP
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Joined: 22 Oct 2006
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Schools: Chicago Booth '11
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A group of men and women competed in a marathon. Before the [#permalink] New post 03 Apr 2007, 09:40
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A group of men and women competed in a marathon. Before the competition, each competitor was weighed and the average weight of the female competitors was found to be 120 lbs, while the average weight of the men was found to be 150 lbs. What was the average weight of all of the competitors?

(1) 100 men competed in the marathon.
(2) There were twice as many men as women competing in the marathon.
Manager
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Joined: 14 Mar 2007
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 [#permalink] New post 03 Apr 2007, 10:21
For me it is B, since:

a) insuff. you just know number of men

b) suff. you can stablish a relation between men and women and find the average weight.
Director
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 [#permalink] New post 03 Apr 2007, 17:56
Should be 'B'.

The average of the group = total weight of the group/number of males and females in the group.

Stmt 2:
Suppose men are = 2n
women = n
total weight of the group =(n*150 +2n*120)/3n = can be solved
Hence SUFF.
Senior Manager
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 [#permalink] New post 04 Apr 2007, 05:39
Clear B.

A) insuff - u don't know the number of women

B) suff - knowing proportions is suff because u can always reduce numbers to proportions (i.e. 100 men 200 women = 1/2 men to women ratio)

:)
  [#permalink] 04 Apr 2007, 05:39
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A group of men and women competed in a marathon. Before the

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