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# A group of men and women competed in a marathon. Before the

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VP
Joined: 22 Oct 2006
Posts: 1443
Schools: Chicago Booth '11
Followers: 8

Kudos [?]: 156 [0], given: 12

A group of men and women competed in a marathon. Before the [#permalink]  03 Apr 2007, 09:40
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Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions
A group of men and women competed in a marathon. Before the competition, each competitor was weighed and the average weight of the female competitors was found to be 120 lbs, while the average weight of the men was found to be 150 lbs. What was the average weight of all of the competitors?

(1) 100 men competed in the marathon.
(2) There were twice as many men as women competing in the marathon.
Manager
Joined: 14 Mar 2007
Posts: 236
Followers: 1

Kudos [?]: 1 [0], given: 0

For me it is B, since:

a) insuff. you just know number of men

b) suff. you can stablish a relation between men and women and find the average weight.
Director
Joined: 14 Jan 2007
Posts: 779
Followers: 2

Kudos [?]: 76 [0], given: 0

Should be 'B'.

The average of the group = total weight of the group/number of males and females in the group.

Stmt 2:
Suppose men are = 2n
women = n
total weight of the group =(n*150 +2n*120)/3n = can be solved
Hence SUFF.
Senior Manager
Joined: 11 Feb 2007
Posts: 356
Followers: 1

Kudos [?]: 47 [0], given: 0

Clear B.

A) insuff - u don't know the number of women

B) suff - knowing proportions is suff because u can always reduce numbers to proportions (i.e. 100 men 200 women = 1/2 men to women ratio)

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