A has 300 bags (comprising some 100 lb and some 200 lb) with : PS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 24 Jan 2017, 05:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# A has 300 bags (comprising some 100 lb and some 200 lb) with

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
SVP
Joined: 05 Apr 2005
Posts: 1731
Followers: 5

Kudos [?]: 74 [0], given: 0

A has 300 bags (comprising some 100 lb and some 200 lb) with [#permalink]

### Show Tags

18 May 2005, 05:32
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

A has 300 bags (comprising some 100 lb and some 200 lb) with an average of 180 lb. how many bags should A remove to get 140 lb as average weight of the bags.
VP
Joined: 13 Jun 2004
Posts: 1118
Location: London, UK
Schools: Tuck'08
Followers: 7

Kudos [?]: 45 [0], given: 0

### Show Tags

18 May 2005, 07:23
(100x+200y)/(x+y)=180
finally you'll end up with y=4x
knowing that x+y=300, you find that x=60 and y=240

Even with X=0 you can see that the average is already > 140 so we can deduce that we will certainly have to move some 200 lbs bags.

let's call V the number of 200 lbs bags we would need if we keep the 60*100lbs :
200V+60(100)/V+60 = 140 ; 200V+6000=140V+840 ; 6V=240
V=40

As we know Y=240, we can see that we need to remove 200 bags to reach 40 bags (240-200=40)

Answer should be 200 bags
Senior Manager
Joined: 15 Mar 2005
Posts: 419
Location: Phoenix
Followers: 2

Kudos [?]: 26 [0], given: 0

Re: PS: Bags [#permalink]

### Show Tags

18 May 2005, 14:28
HIMALAYA wrote:
A has 300 bags (comprising some 100 lb and some 200 lb) with an average of 180 lb. how many bags should A remove to get 140 lb as average weight of the bags.

Is it a selective removal of 200lb bags? (I mean this is obvious, but just to confirm- If you remove bags randomly, then the average would tend to 150 lbs, and would not approach 140).

If n bags of 200lbs each are removed,

180x300 - 200n / (300-n) = 140
Solving for n, 54000 - 200 n = 42000 - 140n => 12000 = 60n => n = 200
_________________

Who says elephants can't dance?

Re: PS: Bags   [#permalink] 18 May 2005, 14:28
Display posts from previous: Sort by

# A has 300 bags (comprising some 100 lb and some 200 lb) with

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.