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A high school has 400 students 1/2 attend the airthmetic [#permalink]
 17 Mar 2011, 15:55
Question Stats:
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54% (02:25) wrong based on 0 sessions
A high school has 400 students 1/2 attend the airthmetic club, 5/8 attend the biology club and 3/4 attend the chemistry club. 3/8 attend all 3 clubs. If every student attends at least one club how many students attend exactly 2 clubs. A. 50 B. 75 C. 150 D. 200 E. 300 can you please solve this using a 3 circle venn diagram
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Last edited by rxs0005 on 18 Mar 2011, 04:27, edited 1 time in total.
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Re: venn diagram 3 sets problem [#permalink]
18 Mar 2011, 05:50
rxs, a venn diagram is not necessary for this question, though it may help you visualize the solution.
Basically, this question is asking you to figure out how many students are being double-counted.
A-Club has 200 members (1/2 of 400)
B-Club has 250 members (5/8 of 400)
C-Club has 300 members (3/4 of 400)
If you add these numbers up, you can see that the three clubs combined have 750 students.
The difference between 750 and 400 is due to students being double or triple counted because they are in more than one club.
We can create an equation to solve this:
200+250+300 = n + x + 2y
where n is the number of students, x is the number of students in two clubs, and y is the number of students in three clubs.
The question provides y for us (150).
750 = 400 + x + 300
x = 50
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Re: venn diagram 3 sets problem [#permalink]
18 Mar 2011, 07:10
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Re: venn diagram 3 sets problem [#permalink]
18 Mar 2011, 07:34
thanks i need some clarification on the below For the set overlap i have the below formula Total = A + B + C - AB - BC - CA - 2ABC ----------- ( 1 ) Applying this i get 400 = 200 + 250 + 300 - ( AB + BC + CA ) - 2* 150 sovling this we get AB + BC + CA = 750 - 400 - 300 = 50 My Q is the Formula ( 1) correct and does AB have only doubly counted values that is unique to only A and B not C right ?
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Re: venn diagram 3 sets problem [#permalink]
18 Mar 2011, 08:10
rxs0005 wrote: thanks i need some clarification on the below
For the set overlap i have the below formula
Total = A + B + C - AB - BC - CA - 2ABC ----------- ( 1 )
Applying this i get
400 = 200 + 250 + 300 - ( AB + BC + CA ) - 2* 150
sovling this we get
AB + BC + CA = 750 - 400 - 300 = 50
My Q is the Formula ( 1) correct
and does AB have only doubly counted values that is unique to only A and B not C right ? The way you used it, the formula looks fine. Please see the following link as well: http://gmatclub.com/forum/overlapping-sets-problems-87628.html#p759888AB have only doubly counted values that is unique to only A and B not C right; rightIn the above formula; Total = A + B + C - AB - BC - CA - 2ABC A = Only A + only AB + only AC + only ABC B = Only B + only AB + only BC + only ABC C = Only C + only AC + only BC + only ABC AB = Only AB, but not C BC = Only BC, but not A AC = Only AC, but not B ABC = Only ABC Total = Only A + Only B + Only C + Only AB + Only AC + Only BC + Only ABC + None
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Re: venn diagram 3 sets problem [#permalink]
19 Mar 2011, 00:21
ABC = 150 A + AB + AC + ABC = 200 B + AB + BC + ABC = 250 C + AC + BC + ABC = 300 A + B + C + 2(AB + BC + AC) + 3ABC = 750 Also, A + B + C + AB + BC + AC + ABC = 400 => AB + BC + AC + 2ABC = 350 => AB + BC + AC = 350 - 300 = 50 Answer - A
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Re: venn diagram 3 sets problem [#permalink]
30 Oct 2011, 07:48
Hi ppl,
I have a really fundamental doubt.
In some places, I see a formula
AuBuC = A + B + C - AnB -BnC - AnC + AnBnC
In others,
AuBuC = A + B + C - AnB -BnC - AnC - 2(AnBnC)
Pls clarify which is correct or when to apply what.
Thanks
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Re: venn diagram 3 sets problem [#permalink]
30 Oct 2011, 07:58
raghupara wrote: Hi ppl,
I have a really fundamental doubt.
In some places, I see a formula
AuBuC = A + B + C - AnB -BnC - AnC + AnBnC
In others,
AuBuC = A + B + C - AnB -BnC - AnC - 2(AnBnC)
Pls clarify which is correct or when to apply what.
Thanks overlapping-sets-problems-87628.html#p759888
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Re: venn diagram 3 sets problem [#permalink]
01 Nov 2011, 10:08
fluke wrote: raghupara wrote: Hi ppl,
I have a really fundamental doubt.
In some places, I see a formula
AuBuC = A + B + C - AnB -BnC - AnC + AnBnC
In others,
AuBuC = A + B + C - AnB -BnC - AnC - 2(AnBnC)
Pls clarify which is correct or when to apply what.
Thanks overlapping-sets-problems-87628.html#p759888Very clear! Thanks Fluke.
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Re: venn diagram 3 sets problem [#permalink]
08 Mar 2012, 03:01
(1/2)+(5/8)+(3/4)-x-2*(3/8)+0=1 x=1/8 1/8*400=50
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Re: A high school has 400 students 1/2 attend the airthmetic [#permalink]
10 Dec 2012, 20:26
The second formula described by Bunuel for 3 overlapping sets works here as well to find the last remaining "exactly" scenario.
Instead of the "in all three groups" value being the variable, the "in exactly 2 groups" is the variable and solve the equation the exact same way.
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Re: A high school has 400 students 1/2 attend the airthmetic
[#permalink]
10 Dec 2012, 20:26
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