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A house seller can deduct 5 percent from the total sales [#permalink]
 29 Sep 2012, 13:32
Question Stats:
23% (00:00) correct
76% (02:04) wrong based on 0 sessions
A house seller can deduct 5 percent from the total sales value. If he has sold 5 houses, and the price of two houses is between $150,000 and $250,000, one of them is $300,000 house, two houses are between $500,000 and 750,000, what is the range of his revenue? A. 450000 B. 510000 C. 570000 D. 660000 E. 780000
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Aeros
"Why are you trying so hard to fit in when you were born to stand out?"
"Do or do not. There is no 'try'..."
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Re: A house seller can deduct 5 percent from the total sales [#permalink]
30 Sep 2012, 00:24
how m i solving it..m unable to get the ans :D
i did like this..where m i wrong??
First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..
150,000+150,000+300000+500000+500000=1600,000
then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...
250,000+250,000+300,000+750,000+750,000=2300,000
1600,000*.05=80,000
2300,000*.05=115,000
1150000-80,000=35000..
i got 35000 ans..bt not any option given..
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Re: A house seller can deduct 5 percent from the total sales [#permalink]
30 Sep 2012, 04:27
Let the first house be sold for 150,000.
Let the 5th house be sold for 750,000.
Difference is 600000
5% of 600000 is 30000 = 570000
Ans: C
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Re: A house seller can deduct 5 percent from the total sales [#permalink]
30 Sep 2012, 08:00
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sanjoo wrote: how m i solving it..m unable to get the ans :D
i did like this..where m i wrong??
First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..
150,000+150,000+300000+500000+500000=1600,000
then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...
250,000+250,000+300,000+750,000+750,000=2300,000
1600,000*.05=80,000
2300,000*.05=115,000
1150000-80,000=35000..
i got 35000 ans..bt not any option given.. Hi, you are almost OK. However, the range is for the total revenue, not for the discounts. (In the example above, I will simplify to smaller numbers) (1) 2(150)+300+2(500) = 1600 1600*0.95=1520 (Revenue considering the minimum values with the discount) (2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount) So, the the revenue range could be = 2300 - 1520 = 780 (Answ E)
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Aeros
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Re: A house seller can deduct 5 percent from the total sales [#permalink]
30 Sep 2012, 12:34
aeros232 wrote: sanjoo wrote: how m i solving it..m unable to get the ans :D
i did like this..where m i wrong??
First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..
150,000+150,000+300000+500000+500000=1600,000
then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...
250,000+250,000+300,000+750,000+750,000=2300,000
1600,000*.05=80,000
2300,000*.05=115,000
1150000-80,000=35000..
i got 35000 ans..bt not any option given.. Hi, you are almost OK. However, the range is for the total revenue, not for the discounts. (In the example above, I will simplify to smaller numbers) (1) 2(150)+300+2(500) = 1600 1600*0.95=1520 (Revenue considering the minimum values with the discount) (2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount) So, the the revenue range could be = 2300 - 1520 = 780 (Answ E) R u sure?? its E? what i think to get maximum range..we should make another mean 2300 should be taken minimum.
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Re: A house seller can deduct 5 percent from the total sales [#permalink]
25 Nov 2012, 20:17
sanjoo wrote: aeros232 wrote: sanjoo wrote: how m i solving it..m unable to get the ans :D
i did like this..where m i wrong??
First I consider , least value of first 2 homes which is 150,000..and least value of last two homes 500,000..
150,000+150,000+300000+500000+500000=1600,000
then I have taken max value of first two houses. 250,000, and max value of last two houses, which 750,000...
250,000+250,000+300,000+750,000+750,000=2300,000
1600,000*.05=80,000
2300,000*.05=115,000
1150000-80,000=35000..
i got 35000 ans..bt not any option given.. Hi, you are almost OK. However, the range is for the total revenue, not for the discounts. (In the example above, I will simplify to smaller numbers) (1) 2(150)+300+2(500) = 1600 1600*0.95=1520 (Revenue considering the minimum values with the discount) (2) 2(250)+300+2(750) = 2300 (Revenue considering the maximum values without the discount) So, the the revenue range could be = 2300 - 1520 = 780 (Answ E) R u sure?? its E? what i think to get maximum range..we should make another mean 2300 should be taken minimum. Sorry but why didn t you deducted from the 2300 the 115??? Thus the range is 665,000. The answer is def not E Please give some feedback, Thanks  Posted from GMAT ToolKit
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Re: A house seller can deduct 5 percent from the total sales
[#permalink]
25 Nov 2012, 20:17
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