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  A husband and wife started painting their house, but husband [#permalink]
New postPosted: Wed Apr 22, 2009 5:24 am 
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A husband and wife, started painting their house, but husband left painting 5 days before the completion of the work. How many days will it take to complete the work, which the husband alone would have completed in 20 days and wife in 15 days?
A. 40/7
B. 50/7
C. 75/7
D. 55/7
[Reveal] Spoiler: OA
C


Last edited by Bunuel on Fri Jan 27, 2012 10:47 am, edited 1 time in total.
Added the OA


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  Re: Work & Rate problem [#permalink]
New postPosted: Wed Apr 22, 2009 8:26 am 
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H take 20 days = 1
W take 15 days = 1
H one day work = 1/20 and W one day work = 1/15

H + W one day work = 1/20 + 1/15 = 7/60.

In a total of T day H+W worked for T-5 and W alone for 5

(7/60) (T-5) + 1/15 * 5 = 1 therefore T = 75/7

Ans : C


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  Re: Work & Rate problem [#permalink]
New postPosted: Sat Sep 05, 2009 3:39 am 
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With the answer choices given there's a faster way.

There is no need to solve the whole thing.

Using the rate eqn for combined work... 1/20 + 1/15 = 7/60

So it would take 60/7 days combined. If the Husband quits working a few days earlier... total time is going to be > 60/7. There is only one value > 60/7 so answer is 75/7


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  Re: Work & Rate problem [#permalink]
New postPosted: Wed Apr 22, 2009 8:05 am 
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johnnybravo86 wrote:
Please help me solve this problem

A husband and wife, started painting their house, but husband left painting 5 days before the completion of the work. How many days will it take to complete the work, which the husband alone would have completed in 20 days and wife in 15 days?

a) 40/7 b)50/7 c)75/7 d) 55/7


It's a multiple step problem: 1) figure out how many days (D) it would take the husband and wife to complete the job working together, 2) figure out how much of the house would be painted in D-5 days, 3) figure out how long it would take the wife to paint the remaining portion

1. How many days would it take the husband and wife to complete the house working together?

Each day, the husband can paint 1/20 of the house, and the wife can paint 1/15 of the house, so combined they can paint (1/20 + 1/15 = 7/60) of the house.

At that rate it would take them 60/7 days to complete the house. (7/60 house/day * 60/7 days = 1 house)

2. How much of the house can they paint in D-5 days?

(D-5 = 60/7 - 35/7 = 25/7) If working together they paint 7/60 of the house per day, then in D-5 days they could paint:

7/60 house/day * 25/7 days = 175/420 = 5/12 of the house will be painted in D-5 days.

3. How long will it take the wife, working alone, to paint this portion of the house?

The wife can paint 1/15 of the house each day, and there is 5/12 of the house that needs to be painted, so it would take her (5/12) / (1/15) = 25/4 days.

Well, I've checked my math a few times and came up with the same answer, which isn't one of the options presented. Where did the question come from?

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  Re: Work & Rate problem [#permalink]
New postPosted: Sat Sep 05, 2009 4:58 pm 
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tkarthi4u wrote:
H take 20 days = 1
W take 15 days = 1
H one day work = 1/20 and W one day work = 1/15

H + W one day work = 1/20 + 1/15 = 7/60.

In a total of T day H+W worked for T-5 and W alone for 5

(7/60) (T-5) + 1/15 * 5 = 1 therefore T = 75/7

Ans : C


Hey guys, can someone explain to my why it (1/5*5) since the question is asking how long it will take to complete the work. I would assume that if it is the women alone, it would now take longer than 5 days to complete the paint job?


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  Re: Work & Rate problem [#permalink]
New postPosted: Sun Sep 06, 2009 5:28 am 
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dhushan wrote:
tkarthi4u wrote:
H take 20 days = 1
W take 15 days = 1
H one day work = 1/20 and W one day work = 1/15

H + W one day work = 1/20 + 1/15 = 7/60.

In a total of T day H+W worked for T-5 and W alone for 5

(7/60) (T-5) + 1/15 * 5 = 1 therefore T = 75/7

Ans : C


Hey guys, can someone explain to my why it (1/5*5) since the question is asking how long it will take to complete the work. I would assume that if it is the women alone, it would now take longer than 5 days to complete the paint job?


I agree with you dhushan, the structure of the question is vague. It should have asked "how long did it take to complete the housing painting?" Cause my understanding of the question also narrowed down to how many days will it take the wife to complete the job.
I doubt that GMAC will structure the question the same way.


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  Re: Work & Rate problem [#permalink]
New postPosted: Sun Sep 06, 2009 5:49 am 
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consider this:-
husband 1 day work=1/20.....wife 1 day work=1/15.. combined 1 day work=1/20+1/15=7/60
last 5 days women worked alone , so fractin of work completed by her in those 5 days=5*1/15=1/3..
remaining work was completed by both .. so time taken=(fraction of work left)/(combined 1 day work)=(2/3)/(7/60)..
or (2*60)/(3*7)=40/7...
total days=5+40/7=75/7...


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  Re: Work & Rate problem [#permalink]
New postPosted: Tue Oct 27, 2009 9:02 am 
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Sol1 :
First, in 5 days, the wife work 5/15 or 1/3 of the job
Then, together, they use (2/3)(60/7) = 40/7 days to finish 2/3 of the job
Thus, in total, use 75/7

Sol2: together, they use 60/7 days to finish the job. Thus, if the husband stops working, it has to take more than 60/7 days to finish the job.


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  Re: Work & Rate problem [#permalink]
New postPosted: Tue Oct 27, 2009 11:01 am 
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Let us assume that H+W work together for x days.

so ,

7/60 * (x-5) + 1/3 = 1

7/20(x-5) = 2

or X = 75/7

I will choose option C


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  Re: Work & Rate problem [#permalink]
New postPosted: Sun Feb 07, 2010 9:36 pm 
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Husband alone can complete the work in 20 days
i.e in one day he does 5% of work

Wife alone can complete the work in 15 days
i.e. in one day she does 6.67% of work

During last three days she worked alone i.e. she completed 33.33% (5* 6.67%) of work working alone.

Both of them working together did = 100-33.33 = 66.67% of work

Therefore no. days for which they worked together = 66.67%/(5%+6.67%) = 66.67/11.67 = 5 point something
Total days = 5 +5 point something = 10 point something
From options = 75/7 = 10 point something
(C)


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  Re: Work & Rate problem [#permalink]
New postPosted: Sun Sep 11, 2011 6:36 am 
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Good reasoning bharath...

That is a good way to solve this problem. It took 1.3 min for me to solve this problem with your approach it takes less than 30sec.... :)


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  Re: Work & Rate problem [#permalink]
New postPosted: Fri Jan 27, 2012 9:39 am 
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x = total time of work

x-5/20 = husband's work time
x/15 = wife's work time

x-5/20 + x/15 = total work time for wife, when working together

3x-15/60 + 4x/60= 1

7x-15=60

7x=75

x=75/7


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  Re: Work & Rate problem [#permalink]
New postPosted: Fri Jan 27, 2012 10:44 am 
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A husband and wife, started painting their house, but husband left painting 5 days before the completion of the work. How many days will it take to complete the work, which the husband alone would have completed in 20 days and wife in 15 days?
A. 40/7
B. 50/7
C. 75/7
D. 55/7

As pointed out above there are several ways to solve this problem. Below are probably two shortest approaches:

Approach #1:
Rate of husband \frac{1}{20} job/day;
Rate of wife \frac{1}{15} job/day;
Combined rate: \frac{1}{20}+\frac{1}{15}=\frac{7}{60} job/day;

During the last 5 days, when the wife worked alone, she completed \frac{5}{15}=\frac{1}{3}rd of the job;
Hence, remaining \frac{2}{3}rd of the job was done by them working together in time=\frac{job'}{rate}=\frac{(\frac{2}{3})}{(\frac{7}{60})}=\frac{40}{7} days;

Total time needed to complete the whole job: 5+\frac{40}{7}=\frac{75}{7} days.

Answer: C.

Approach #2:
It's based on observing the answer choices. On the PS section always look at the answer choices before you start to solve a problem. They might often give you a clue on how to approach the question.

Combined rate of the husband and wife is \frac{7}{60} job/day, which means that working together they'll complete the job in \frac{60}{7} days (time is reciprocal of rate). As they worked together only some part of the total time, then actual time would be more than \frac{60}{7} days. Only \frac{75}{7} is more than this value (answer choice C), so it must be correct.

Answer: C.

Hope it helps.

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  Re: Work & Rate problem [#permalink]
New postPosted: Mon Feb 06, 2012 11:14 am 
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Bunuel wrote:
A husband and wife, started painting their house, but husband left painting 5 days before the completion of the work. How many days will it take to complete the work, which the husband alone would have completed in 20 days and wife in 15 days?
A. 40/7
B. 50/7
C. 75/7
D. 55/7

As pointed out above there are several ways to solve this problem. Below are probably two shortest approaches:

Approach #1:
Rate of husband \frac{1}{20} job/day;
Rate of wife \frac{1}{15} job/day;
Combined rate: \frac{1}{20}+\frac{1}{15}=\frac{7}{60} job/day;

During the last 5 days, when the wife worked alone, she completed \frac{5}{15}=\frac{1}{3}rd of the job;
Hence, remaining \frac{2}{3}rd of the job was done by them working together in time=\frac{job'}{rate}=\frac{(\frac{2}{3})}{(\frac{7}{60})}=\frac{40}{7} days;

Total time needed to complete the whole job: 5+\frac{40}{7}=\frac{75}{7} days.

Answer: C.

Approach #2:
It's based on observing the answer choices. On the PS section always look at the answer choices before you start to solve a problem. They might often give you a clue on how to approach the question.

Combined rate of the husband and wife is \frac{7}{60} job/day, which means that working together they'll complete the job in \frac{60}{7} days (time is reciprocal of rate). As they worked together only some part of the total time, then actual time would be more than \frac{60}{7} days. Only \frac{75}{7} is more than this value (answer choice C), so it must be correct.

Answer: C.

Hope it helps.


The question say the husband left the job 5 days back. Then it is never mentioned that he has re-joined. WIth the current wording, doesn't it imply that its only the wife who is going to complete the job . And if thats the case it would take her 15 days as the question itself mentions... May be its just some missing part in the question.


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  Re: Work & Rate problem [#permalink]
New postPosted: Mon Feb 06, 2012 3:09 pm 
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docabuzar wrote:
The question say the husband left the job 5 days back. Then it is never mentioned that he has re-joined. WIth the current wording, doesn't it imply that its only the wife who is going to complete the job . And if thats the case it would take her 15 days as the question itself mentions... May be its just some missing part in the question.


It seems that you misinterpreted the question. We are told that: "a husband and wife, started painting, but husband left 5 days before the completion of the work". So the husband worked 5 fewer days than the wife (he didn't rejoined).

Next, part of the question just tells us the individual rates of the husband and the wife: the husband alone can complete the painting in 20 days and wife in 15 days.

The actual time it took for them to complete the painting would obviously be less than 15 as the part of the time they were working together.

Hope it's clear.

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  Re: Work & Rate problem [#permalink]
New postPosted: Fri Feb 17, 2012 10:44 am 
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Bunuel wrote:
docabuzar wrote:
The question say the husband left the job 5 days back. Then it is never mentioned that he has re-joined. WIth the current wording, doesn't it imply that its only the wife who is going to complete the job . And if thats the case it would take her 15 days as the question itself mentions... May be its just some missing part in the question.


It seems that you misinterpreted the question. We are told that: "a husband and wife, started painting, but husband left 5 days before the completion of the work". So the husband worked 5 fewer days than the wife (he didn't rejoined).

Next, part of the question just tells us the individual rates of the husband and the wife: the husband alone can complete the painting in 20 days and wife in 15 days.

The actual time it took for them to complete the painting would obviously be less than 15 as the part of the time they were working together.

Hope it's clear.


Thanks for the explanation.

Actually what I interpreted from the last part of the question is - the times given (20 days & 15 days) would be required to complete the "remaining part of job" and not the complete job.

Do you think what i interpreted can be the case. ?


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  Re: Work & Rate problem [#permalink]
New postPosted: Fri Feb 17, 2012 1:53 pm 
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docabuzar wrote:
Thanks for the explanation.

Actually what I interpreted from the last part of the question is - the times given (20 days & 15 days) would be required to complete the "remaining part of job" and not the complete job.

Do you think what i interpreted can be the case. ?


We are told that " husband left painting 5 days before the completion of the work (by wife)", so wife needed 5 days to complete the remaining job, not 15. So, your interpretation can not be correct.

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