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# A is the first term in a set of consecutive numbers which

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Senior Manager
Joined: 19 Feb 2004
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A is the first term in a set of consecutive numbers which [#permalink]  19 Feb 2004, 08:16
A is the first term in a set of consecutive numbers which consists of n terms. Which of the following expresses the last term of the set?
a. A+n
b. 2A+n
c. (2A+n)/2
d. A+n-1
e. A+2n
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Joined: 11 Nov 2003
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Re: Algebramisc#9 [#permalink]  19 Feb 2004, 15:36
batliwala wrote:
A is the first term in a set of consecutive numbers which consists of n terms. Which of the following expresses the last term of the set?
a. A+n
b. 2A+n
c. (2A+n)/2
d. A+n-1
e. A+2n

I have a question. Does consecutive numbers means consecutive integers? What would we call numbers 1.1, 1.2, 1.3, 1.4? Can they also be called consecutive numbers? If so, then I think the above question should specify the word "consecutive integers"
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1.1, 1.2, 1.3, 1.4,............. are called decimal numbers and not just numbers. Integers are numbers which are both +ve an -ve like -2,-1,0,1,2......... . 0 is neither +ve nor -ve number.
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ans is D. plug in A= 1 and n terms = 4 will give a last term that is 4. All choices except D can be eliminated.
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rakesh1239 wrote:
1.1, 1.2, 1.3, 1.4,............. are called decimal numbers and not just numbers. Integers are numbers which are both +ve an -ve like -2,-1,0,1,2......... . 0 is neither +ve nor -ve number.

Rakesh,

When the problem statement uses just the word "numbers", you can consider both integers as well as decimal numbers. You can not assume the either way. You can consider integers only when the word "integer" is explicitly used in the problem statement. Here, in this problem the word "integer" is not used. So it could be either integer or decimal numbers. I agree that answer is D but only if we assume the numbers to be integers. So I just think that the problme statement should have used the word "integers".
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