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A jet is flying 2400 miles from Hawaii to San Francisco. In

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A jet is flying 2400 miles from Hawaii to San Francisco. In [#permalink] New post 05 Jan 2005, 09:32
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A jet is flying 2400 miles from Hawaii to San Francisco. In still
air, it flies at 600 mph. There is a 40 mph tailwind. How many hours
after takeoff would it be faster to just go to San Francisco than to
return to Hawaii in the case of an emergency?
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Re: PS: Jet Problem [#permalink] New post 05 Jan 2005, 10:02
schumacher wrote:
A jet is flying 2400 miles from Hawaii to San Francisco. In still
air, it flies at 600 mph. There is a 40 mph tailwind. How many hours
after takeoff would it be faster to just go to San Francisco than to
return to Hawaii in the case of an emergency?


hi here is the solution.
Bcos of 40 mph tailwind avg speed is 600 + 40 = 640 mph.

2400/640 = 3.75 hrs

so if plane has travelled more that half then it makes sense to go to san francisco ..that hawii.....

so ...3.75/2 = 1.875 hrs is the answer !!!!!!!!!!!!!

Thanks :-D
Prince

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 [#permalink] New post 05 Jan 2005, 10:36
semaphore,

When the plane returns, the speed decreases to 540mph only. How can we incorporate this piece of information into the question?

According to your answer, the speed of plane to SF from H is the same as the speed from H to SF. :stupid
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 [#permalink] New post 05 Jan 2005, 10:52
I am getting 2.1 hrs.

I however took the speed as (600 - 40 = 560).

What's the OA ?
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 [#permalink] New post 05 Jan 2005, 13:00
2 Hours

Speed = distance / time

time = distance / speed

relative velocity from SF -> Hawaii = 640 kmph
relative velocity from Hawaii -> SF = 560 kmph

Consider that the jet is x km from Hawaii when it has to return

at this point in time, the jet is 2400 - x km from SF

Equating the time:

(2400 - x) / 640 = x / 560

Solving for x, we get x = 1120 which implies, the jet is 1280 from SF. At 640 kmph, it would take the jet 2 hours to cover this distance.
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 [#permalink] New post 05 Jan 2005, 13:34
maaverick wrote:
2 Hours

Speed = distance / time

time = distance / speed

relative velocity from SF -> Hawaii = 640 kmph
relative velocity from Hawaii -> SF = 560 kmph

Consider that the jet is x km from Hawaii when it has to return

at this point in time, the jet is 2400 - x km from SF

Equating the time:

(2400 - x) / 640 = x / 560

Solving for x, we get x = 1120 which implies, the jet is 1280 from SF. At 640 kmph, it would take the jet 2 hours to cover this distance.


Exactly the same approach I used. The only difference was I used the 1120 as the distance already traveled and reasoned if you had to fly back you'd go at 560. So the time would be D/R=1120/560=28/14=2 hours. The same basic idea but this way saves subtracting 1120 from 2400.
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 [#permalink] New post 05 Jan 2005, 14:03
Quote:
2 Hours

Speed = distance / time

time = distance / speed

relative velocity from SF -> Hawaii = 640 kmph
relative velocity from Hawaii -> SF = 560 kmph

Consider that the jet is x km from Hawaii when it has to return

at this point in time, the jet is 2400 - x km from SF

Equating the time:

(2400 - x) / 640 = x / 560

Solving for x, we get x = 1120 which implies, the jet is 1280 from SF. At 640 kmph, it would take the jet 2 hours to cover this distance.



You are almost right. The question asks for the time already traveled, not the time that would take to complete the journey (either to Hawaii or to San Francisco)!!

Imagine that the plane had travelled t hours from Hawaii. It would have covered 640t miles (you are trying to determine at this point whether to go back or continue with the journey). Remaining distance to cover is 2400-640t miles. If you were to proceed, time it would take would be (2400-640t)/640. If you were to go back, the time that would take is 640t/560

Solving for t, we get 1.75 hours. This is the time from the take off.
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 [#permalink] New post 06 Jan 2005, 09:27
I agree with maaverick's answer. His wording in the last sentence is a bit confusing, but I think his point is if the plane leaves Hawaii 2 hours, it would be faster for the pilot to fly directly to SF than returning to Hawaii.
He does not mean the remaining time to reach SF when the plane is in the air is 2 hours.

Very nice approach from Maaverick. Correct me if I misinterpret your solution, Mavverick.

Last edited by jinino on 06 Jan 2005, 13:02, edited 2 times in total.
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 [#permalink] New post 06 Jan 2005, 12:47
Can someone please explain to me what exactly tailwind means, I am unsure on how r we saying that:

relative velocity from SF -> Hawaii = 640 kmph
relative velocity from Hawaii -> SF = 560 kmph
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 [#permalink] New post 06 Jan 2005, 13:01
Tailwind here means the wind blows with the same direction when the plan travels from Hawaii to SF. It will make the plane faster in the direction from Hawaii to SF, but slower in the other way around.
This is my interpretation, and pls correct me if I am wrong.
  [#permalink] 06 Jan 2005, 13:01
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