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# A lady grows cabbages in her garden that is in the shape of

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Senior Manager
Joined: 19 Apr 2008
Posts: 325
Followers: 3

Kudos [?]: 42 [0], given: 0

A lady grows cabbages in her garden that is in the shape of [#permalink]  17 May 2008, 15:51
A lady grows cabbages in her garden that is in the shape of a square. Each cabbage takes 1 square feet of area in her garden. This year, she has increased her output by 211 cabbages as compared to last year. The shape of the area used for growing the cabbages has remained a square in both these years. How many cabbages did she produce this year?

sorry , no options .
Director
Joined: 23 Sep 2007
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Re: interesting question [#permalink]  17 May 2008, 16:48
2
KUDOS
I got this from a search

A lady grows cabbages in her garden that is in the shape of a square. Each cabbage takes 1 square feet of area in her garden. This year, she has increased her output by 211 cabbages as compared to last year. The shape of the area used for growing the cabbages has remained a square in both these years. How many cabbages did she produce this year?

A. 11236
B. 11025
C. 14400
D. 12696
E. Cannot be determined

The correct choice is (A) and the correct answer is 11236.

The shape of the area used for growing cabbages has remained a square in both the years.

Let the side of the square area used for growing cabbages this year be X ft.
Therefore, the area of the ground this year = X^2 sq.ft.

And let the side of the square area used for growing cabbages last year be Y ft.
Therefore, the area of the ground used last year = Y^2 sq.ft.

As the number of cabbages grown has increased by 211, the area would have increased by 211 sq ft as each cabbage takes 1 sq ft space.

Hence X^2 - Y^2 = 211 => (X + Y)(X – Y) = 211.
211 is a prime number and hence it will have only two factors. i.e., 211 = 211*1.
This can be represented as (106 + 105)*(106-105).

(X + Y)(X – Y) = (106 + 105)(106 – 105).
From this we can deduce that X = 106 and Y = 105.

Therefore, number of cabbages produced this year = X^2 = 1062 = 11236.
Senior Manager
Joined: 20 Feb 2008
Posts: 296
Location: Bangalore, India
Schools: R1:Cornell, Yale, NYU. R2: Haas, MIT, Ross
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Re: interesting question [#permalink]  17 May 2008, 18:32
gmatnub wrote:
I got this from a search

A lady grows cabbages in her garden that is in the shape of a square. Each cabbage takes 1 square feet of area in her garden. This year, she has increased her output by 211 cabbages as compared to last year. The shape of the area used for growing the cabbages has remained a square in both these years. How many cabbages did she produce this year?

A. 11236
B. 11025
C. 14400
D. 12696
E. Cannot be determined

The correct choice is (A) and the correct answer is 11236.

The shape of the area used for growing cabbages has remained a square in both the years.

Let the side of the square area used for growing cabbages this year be X ft.
Therefore, the area of the ground this year = X^2 sq.ft.

And let the side of the square area used for growing cabbages last year be Y ft.
Therefore, the area of the ground used last year = Y^2 sq.ft.

As the number of cabbages grown has increased by 211, the area would have increased by 211 sq ft as each cabbage takes 1 sq ft space.

Hence X^2 - Y^2 = 211 => (X + Y)(X – Y) = 211.
211 is a prime number and hence it will have only two factors. i.e., 211 = 211*1.
This can be represented as (106 + 105)*(106-105).

(X + Y)(X – Y) = (106 + 105)(106 – 105).
From this we can deduce that X = 106 and Y = 105.

Therefore, number of cabbages produced this year = X^2 = 1062 = 11236.

Good one I used the same trick but instead of putting it into a formula I tried finding the squares of numbers that when you subtract 211 results in a square. I could not be bothered to try more than 40, clearly I was a long way off!
Re: interesting question   [#permalink] 17 May 2008, 18:32
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# A lady grows cabbages in her garden that is in the shape of

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