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# A large rectangle can be divided into 12 small rectangles of

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A large rectangle can be divided into 12 small rectangles of [#permalink]  19 Sep 2007, 19:53
A large rectangle can be divided into 12 small rectangles of the same size. What is the perimeter of the large rectangle?

1) Small rectangular perimeter is 300
2) large rectangular area of 60,000
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Re: Rectangle [#permalink]  19 Sep 2007, 20:13
jtai wrote:
A large rectangle can be divided into 12 small rectangles of the same size. What is the perimeter of the large rectangle?

1) Small rectangular perimeter is 300
2) large rectangular area of 60,000

I think C.
Stmtn1

If x and y are small dimensions , then we have 2(x+y) = 300
Large perimter would be 4(x+y) + 2(2x +y ) . Can get the answer
So not suff .

Stmtn 2
4x * 3y = 13xy = 60000
Not suff .

Combining, I guess we have a solution as we have 2 equations and 2 variables.
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Re: Rectangle [#permalink]  19 Sep 2007, 21:06
jtai wrote:
A large rectangle can be divided into 12 small rectangles of the same size. What is the perimeter of the large rectangle?

1) Small rectangular perimeter is 300
2) large rectangular area of 60,000

let sides of small rectangle be a and b. so we have

from stmt 1: a + b = 150

we have 12 such rectangles and they can be arranged as (6,2) (4,3) or (12,1). lets say if its 6,2 then we need to find 2(6a + 2b). Which cannot be derived.

from statement 2 we know the area which is 60000

now for all the above combinations we know that are would be 12ab ( 6*2 or 4*3 or 12*1)

so we have 12ab = 60000 or ab = 5000. but again since we do not know the exact arrangement we do not know the perimeter.

combining both we have a +b = 150 and ab = 5000 so a = 100 b = 50 or b = 100 a = 50. we still cant find the perimeter, as we do not know the combination. so answer is E.
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Re: Rectangle [#permalink]  19 Sep 2007, 22:53
carpeD wrote:
jtai wrote:
A large rectangle can be divided into 12 small rectangles of the same size. What is the perimeter of the large rectangle?

1) Small rectangular perimeter is 300
2) large rectangular area of 60,000

let sides of small rectangle be a and b. so we have

from stmt 1: a + b = 150

we have 12 such rectangles and they can be arranged as (6,2) (4,3) or (12,1). lets say if its 6,2 then we need to find 2(6a + 2b). Which cannot be derived.

from statement 2 we know the area which is 60000

now for all the above combinations we know that are would be 12ab ( 6*2 or 4*3 or 12*1)

so we have 12ab = 60000 or ab = 5000. but again since we do not know the exact arrangement we do not know the perimeter.

combining both we have a +b = 150 and ab = 5000 so a = 100 b = 50 or b = 100 a = 50. we still cant find the perimeter, as we do not know the combination. so answer is E.

I agree with your explination
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Re: Rectangle [#permalink]  19 Sep 2007, 23:14
carpeD wrote:
jtai wrote:
A large rectangle can be divided into 12 small rectangles of the same size. What is the perimeter of the large rectangle?

1) Small rectangular perimeter is 300
2) large rectangular area of 60,000

let sides of small rectangle be a and b. so we have

from stmt 1: a + b = 150

we have 12 such rectangles and they can be arranged as (6,2) (4,3) or (12,1). lets say if its 6,2 then we need to find 2(6a + 2b). Which cannot be derived.

from statement 2 we know the area which is 60000

now for all the above combinations we know that are would be 12ab ( 6*2 or 4*3 or 12*1)

so we have 12ab = 60000 or ab = 5000. but again since we do not know the exact arrangement we do not know the perimeter.

combining both we have a +b = 150 and ab = 5000 so a = 100 b = 50 or b = 100 a = 50. we still cant find the perimeter, as we do not know the combination. so answer is E.

I also agree. I got down to C and E. And even w/ stmnts combined I didn't think C was enough. Ran outta time. This is a great explanation!
Re: Rectangle   [#permalink] 19 Sep 2007, 23:14
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