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# A light string has 10 bulbs, if one bulb fail, all the other

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Director
Joined: 08 Jul 2004
Posts: 604
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A light string has 10 bulbs, if one bulb fail, all the other [#permalink]  01 Oct 2004, 05:28
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A light string has 10 bulbs, if one bulb fail, all the other bulb will fail, the probability for one bulb to fail is 0.06,what is the probability for no bulb to fail?
Intern
Joined: 20 Mar 2003
Posts: 19
Location: New York
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Kudos [?]: 0 [0], given: 0

ok i'll take a crack at it...but i dont know if this is right.

The probability of one failing is 0.6. So, 0.06*10=.60 is the probability that one of the 10 will fail. The probability of one not failing is 1-.60 = .40.

Not sure if this is right, just trying to get involved with the forum and learn from others and give my thought process.

Thanks
Director
Joined: 08 Jul 2004
Posts: 604
Followers: 2

Kudos [?]: 82 [0], given: 0

I reckon it should be 0.94^10 but I am not sure. Will wait for gurus to respond!!
S
Director
Joined: 16 Jun 2004
Posts: 893
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Kudos [?]: 19 [0], given: 0

Prob that one bulb will not fail = 1-0.06=0.94
Prob that none of the 10 bulbs fail = (0.94)^10
Director
Joined: 08 Jul 2004
Posts: 604
Followers: 2

Kudos [?]: 82 [0], given: 0

Venks have you made some mistake . Shouldn't it be 1-0.06 or is it something I am missing?
S
Director
Joined: 16 Jun 2004
Posts: 893
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Kudos [?]: 19 [0], given: 0

Yes, I realised my mistake (took 0.6 instead of 0.06). I have edited my earlier post.
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