Hi All,

Based on the wording of this prompt, there's a great way to 'visualize' the solution by drawing some pictures and doing a little arithmetic:

Since there are no individual people in line (everyone is part of a 'group' from 2 to 6 people), we can think about minimizing or maximizing the number of groups to find out where Samantha's group COULD be in line. We know that she's the 27th person, so we can use that to our advantage.

Let's start by figuring out the maximum number of groups that could be in line AHEAD of Samantha....

By making ALL of those groups as SMALL as possible, we can maximize the number of groups ahead of Samantha:

2 2 2 2 2 2 2 2 2 2 2 2 2 (then Samantha's group)

With thirteen groups of 2, we account for 26 people. Samantha would then be in the NEXT group (regardless of the size). So the LARGEST potential value is 14. Looking at the answer choices, we can eliminate Answers A, B and C (since none of them accounts for 14 groups).

Next we can figure out the minimum number of groups that would be in line AHEAD of Samantha....

By making ALL of those groups as LARGE as possible, we can minimize the number of groups ahead of Samanatha:

6 6 6 6 (then Samantha's group)

With four groups of 6, we account for 24 people. Samantha could then be in the NEXT group. So the SMALLEST potential value is 5. Eliminate Answer E.

Final Answer:

GMAT assassins aren't born, they're made,

Rich

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Official Guide 2016 Question Breakdown:

http://gmatclub.com/forum/empowergmat-blog-198415.html#p1527977

Rich Cohen

Rich.C@empowergmat.com

http://www.empowergmat.com

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