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Re: A line that passes through (–1, –4) and (3, k) has a slope = [#permalink]

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29 Nov 2012, 10:32

1

This post received KUDOS

y=mx+c is the equation. Since the line passes through (-1,-4) and (3,k) substitute this for the value of x and y.

we get 2 equations

-4=-k+c...(1) c=-2k.......(2)

Substitute for C in equation 1. we get k=4/3.

The ans is C.
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This is a considerably more difficult one, which will involve some algebra. Let’s say that the “first” point is (–1, –4) and the “second,” (3, k). The rise = k + 4, which involves a variable. The run = 3 – (–1) = 4. There the slope is (k + 4)/4, and we can set this equal to k and solve for k. (k + 4)/4 = k k + 4 = 4k 4 = 3k k = 4/3

A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?

A. 3/4 B. 1 C. 4/3 D. 2 E. 7/2

Kudos for a correct solution.

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Re: A line that passes through (–1, –4) and (3, k) has a slope = [#permalink]

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26 Aug 2016, 04:28

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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