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A line that passes through (–1, –4) and (3, k) has a slope =

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Magoosh GMAT Instructor
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A line that passes through (–1, –4) and (3, k) has a slope = [#permalink] New post 19 Nov 2012, 16:30
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E

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A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?
(A) 3/4
(B) 1
(C) 4/3
(D) 2
(E) 7/2


See a full discussion of lines & slope in the x-y plane here:
http://magoosh.com/gmat/2012/gmat-math- ... x-y-plane/

Experts: feel free to add any other x-y plane advice you would like to share.
[Reveal] Spoiler: OA

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Re: A line that passes through (–1, –4) and (3, k) has a slope = [#permalink] New post 29 Nov 2012, 10:32
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y=mx+c is the equation. Since the line passes through (-1,-4) and (3,k) substitute this for the value of x and y.

we get 2 equations

-4=-k+c...(1)
c=-2k.......(2)

Substitute for C in equation 1. we get k=4/3.

The ans is C.
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Re: line with variable slope [#permalink] New post 19 Nov 2012, 17:35
mikemcgarry wrote:
A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?
(A) 3/4
(B) 1
(C) 4/3
(D) 2
(E) 7/2


See a full discussion of lines & slope in the x-y plane here:
http://magoosh.com/gmat/2012/gmat-math- ... x-y-plane/

Experts: feel free to add any other x-y plane advice you would like to share.

Slope = (y2-y1)/(x2-x1)
=> k = (k+4)/(3+1)
=> 4k = k+4
=> k =4/3

Ans C it is!
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Re: A line that passes through (–1, –4) and (3, k) has a slope = [#permalink] New post 07 Dec 2012, 03:43
A line that passes through (–1, –4) and (3, k) has a slope = k. What is the value of k?

m = \(\frac{y2-y1}{x2-x1}\)
m = \(\frac{k-(-4)}{3-(-1)}\)

m = \(\frac{k+4}{4}\) & \(m = k\)

\(k = \frac{k+4}{4}\)
\(4k = k+4\)
\(k = 4/3\)

Answer: 4/3
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Re: A line that passes through (–1, –4) and (3, k) has a slope =   [#permalink] 07 Dec 2012, 03:43
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